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Tom [10]
1 year ago
8

Name the three functional groups in the compound pictured.

Chemistry
1 answer:
oksian1 [2.3K]1 year ago
8 0

The three functional groups shown in the image are: ester, alkoxy and carboxyl.

<h3>What are functional groups?</h3>

Chemical properties depend on its structure. Certain properties, too, are attributable to an atomic group ordered in a particular way, apart from the whole of the molecule. Such groups of atoms that determine the chemical properties of compounds are called<em> functional groups</em>.

The functional group can be on the primary, secondary, or tertiary carbon.

Functional groups are often found on molecules of biological importance.

Functional groups are usually formed by a set of elements such as carbon, hydrogen and oxygen, attached to the hydrocarbon chain, giving the molecule characteristics. Can also include other elements such as sulfur or nitrogen.

Molecules can have more than one functional group on it, having different combinations on it that can affect properties of the molecule such as solubility, structure, or reactivity.

Carboxyl groups are usually seen in amino acids, fatty acids and other molecules since it is a fairly common functional group.

Therefore, we can confirm that the three functional groups shown in the image are: ester, alkoxy and carboxyl.

To learn more about functional groups visit: brainly.com/question/14618322?referrer=searchResults

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Answer: They use other organisms for energy

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In addition to not causing damage to the sample, what is another advantage of using a microspectrophotometer to analyze fibers?
Tems11 [23]

Another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.

<h3>What is a microspectrophotometer?</h3>

Microspectrophotometry is a biological technique used to measure the absorption or transmission spectrum of a solid or liquid material in either transmitted or reflected light.

Microspectrophotometry can also measure the emission of light by a sample, which is usually small as the micro implies.

One advantage of microspectrophotometry is that the sample does not get damaged. However,

However, another advantage of advantage of using a microspectrophotometer to analyze fibers asides not causing damage to the sample is that the sample can be quite small.

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2 years ago
The units used to measure heat are?
Akimi4 [234]

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7 0
3 years ago
Part b an "empty" container is not really empty if it contains air. how may moles of nitrogen are in an "empty" two-liter cola b
Sedbober [7]
<span>6.38x10^-2 moles
       First, let's determine how many moles of gas particles are in the two-liter container. The molar volume for 1 mole at 25C and 1 atmosphere is 24.465 liters/mole. So
   2 L / 24.465 L/mol = 0.081749438 mol
       Now air doesn't just consist of nitrogen. It also has oxygen, carbon dioxide, argon, water vapor, etc. and the total number of moles includes all of those other gasses. So let's multiply by the percentage of nitrogen in the atmosphere which is 78%
    0.081749438 mol * 0.78 = 0.063764562 mol.
        Rounding to 3 significant figures gives 6.38x10^-2 moles</span>
4 0
3 years ago
Read 2 more answers
You make an experiment to determine the percent mass of carbon in sugar. You find out that there is 46.63g of carbon in 75.00g o
Aleksandr [31]

Taking into account the definition of percentage composition, the percent composition of carbon in this sample is 62.17%.

<h3>Percentage composition</h3>

The Percentage Composition is a measure of the amount of mass that an element occupies in a compound and indicates the percentage by mass of each element that is part of a compound.

Then, the percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

percentageby mass= \frac{mass of solute}{mass of solution}x100

<h3>This case</h3>

In this case, you know:

  • mass of solute= 46.63 g
  • mass of solution= 75 g

Replacing:

percentageby mass= \frac{46.63 g}{75 g}x100

Solving:

<u><em>percentage by mass= 62.17 %</em></u>

Finally, the percent composition of carbon in this sample is 62.17%.

Learn more about percent composition:

<u>brainly.com/question/24201923?referrer=searchResults</u>

<u>brainly.com/question/9779410?referrer=searchResults</u>

<u>brainly.com/question/17030163?referrer=searchResults</u>

3 0
2 years ago
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