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Yakvenalex [24]
1 year ago
9

2.Please study the figures below which illustrate the steps in the chemical reaction of fluoromethane (CH3F) with a hydroxide io

n (OH-) to form methanol (CH3OH) and a fluoride ion (F-). Each sphere represents a different type of atom according to the following key.Key: black = carbon white =hydrogen red = oxygen blue= fluorine Three molecular structures labeled A, B, and C. A. Two groups of circles. The first group is composed of a white and a red circle. To the right is a black circle in the middle with three small white and one large blue circles attached on it. B. Two groups of circles. The first group is composed of a red circle with a small white circle attached on it, attached to a black circle with three small white circles attached on it. To the right is a big blue circle. C. A group of circles. A small white circle is attached on a red circle. The red circle is attached to a black circle. Three small white circles are attached on the black circle. A big blue circle is attached on the black circle.•Write the balanced chemical equation for this reaction.•Redraw the figures above in the correct order. Be sure to label each molecule in your drawings and describe what is happening at each step of the reaction in as much detail as possible. •Draw an energy diagram to represent this reaction. Be sure to label the axes, the activation energy, and the energies of each step in the reaction.

Chemistry
1 answer:
Monica [59]1 year ago
7 0

1) The names of the molecules

2) Write the chemical equation

OH^-+CH_3F\rightarrow CH_3OH+F^-

3) Balance the chemical equation

1 fluoride in the reactants and 1 fluoride in the products

1 carbon in the reactants and 1 carbon in the products

4 hydrogens in the reactants and four hydrogens in the products

1 oxygen in the reactants and 1 oxygen in the products

Since the number of atoms in the reactants is the same that the number of atoms in the products, the chemical equation is balanced.

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Solid aluminum (AI) and oxygen (O_2) gas react to form solid aluminum oxide (Al_2O_3). Suppose you have 7.0 mol of Al and 9.0 mo
Nimfa-mama [501]

Answer:

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

Explanation:

Step 1: Data given

Numbers of Al = 7.0 mol

Numbers of mol O2 = O2

Molar mass of Al = 26.98 g/mol

Molar mass of O2 = 32 g/mol

Step 2: The balanced equation

4Al(s) + 3O2(g) → 2Al2O3(s)  

Step 3: Calculate limiting reactant

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

Al is the limiting reactant, it will be consumed completely (7 moles).

O2 is in excess.  There will react 3/4 * 7 = 5.25 moles

There will remain 9-5.25 = 3.75 moles

Step 4: Calculate moles Al2O3

For 4 moles Al we'll have 2moles Al2O3

For 7.0 moles of Al we'll have 3.5 moles of Al2O3 produced

Step 5: Calculate mass of Al2O3

Mass Al2O3 = moles Al2O3 * molar mass Al2O3

Mass Al2O3 = 3.5 moles* 101.96 g/mol

Mass Al2O3 = 356.9 grams

There will be formed 3.5 moles of Al2O3 ( 356.9 grams)

3 0
3 years ago
Is boiling eggs chemical or physical practice?
Elden [556K]

Answer:

chemical

Explanation:

because heat is being taken to the egg

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Answer:

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Explanation:

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3 years ago
Which of these properties is physical property of aluminum
Brrunno [24]

Answer:

B. Aluminum is a good conductor of heat

Explanation:

Physical properties are usually those that can be observed using our senses such as color, luster, freezing point, boiling point, melting point, density, hardness and odor. The Physical Properties of Aluminum are as follows: Color : Silvery-white with a bluish tint.

5 0
2 years ago
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A buffer solution contains 0.345 M acetic acid and 0.377 M sodium acetate . If 0.0613 moles of potassium hydroxide are added to
melamori03 [73]

Answer:

pH = 5.54

Explanation:

The pH of a buffer solution is given by the <em>Henderson-Hasselbach (H-H) equation</em>:

  • pH = pKa + log\frac{[CH_3COO^-]}{[CH_3COOH]}

For acetic acid, pKa = 4.75.

We <u>calculate the original number of moles for acetic acid and acetate</u>, using the <em>given concentrations and volume</em>:

  • CH₃COO⁻ ⇒ 0.377 M * 0.250 L = 0.0942 mol CH₃COO⁻
  • CH₃COOH ⇒ 0.345 M * 0.250 L = 0.0862 mol CH₃COOH

The number of CH₃COO⁻ moles will increase with the added moles of KOH while the number of CH₃COOH moles will decrease by the same amount.

Now we use the H-H equation to <u>calculate the new pH</u>, by using the <em>new concentrations</em>:

  • pH = 4.75 + log\frac{(0.0942+0.0613)mol/0.250L}{(0.0862-0.0613)mol/0.250L} = 5.54
6 0
3 years ago
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