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Yakvenalex [24]
1 year ago
9

2.Please study the figures below which illustrate the steps in the chemical reaction of fluoromethane (CH3F) with a hydroxide io

n (OH-) to form methanol (CH3OH) and a fluoride ion (F-). Each sphere represents a different type of atom according to the following key.Key: black = carbon white =hydrogen red = oxygen blue= fluorine Three molecular structures labeled A, B, and C. A. Two groups of circles. The first group is composed of a white and a red circle. To the right is a black circle in the middle with three small white and one large blue circles attached on it. B. Two groups of circles. The first group is composed of a red circle with a small white circle attached on it, attached to a black circle with three small white circles attached on it. To the right is a big blue circle. C. A group of circles. A small white circle is attached on a red circle. The red circle is attached to a black circle. Three small white circles are attached on the black circle. A big blue circle is attached on the black circle.•Write the balanced chemical equation for this reaction.•Redraw the figures above in the correct order. Be sure to label each molecule in your drawings and describe what is happening at each step of the reaction in as much detail as possible. •Draw an energy diagram to represent this reaction. Be sure to label the axes, the activation energy, and the energies of each step in the reaction.

Chemistry
1 answer:
Monica [59]1 year ago
7 0

1) The names of the molecules

2) Write the chemical equation

OH^-+CH_3F\rightarrow CH_3OH+F^-

3) Balance the chemical equation

1 fluoride in the reactants and 1 fluoride in the products

1 carbon in the reactants and 1 carbon in the products

4 hydrogens in the reactants and four hydrogens in the products

1 oxygen in the reactants and 1 oxygen in the products

Since the number of atoms in the reactants is the same that the number of atoms in the products, the chemical equation is balanced.

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As they contain, green pigement they can perform "Photosynthesis" and obtains energy from that process

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7 0
3 years ago
If the rate law for a reaction A → P is rate = 3.37x10-3 M^-1 min-1 [A]^2 and the initial concentration of a is 0.122 M, calcula
DedPeter [7]

Rate = 3.37x10-3 M^-1 min-1 [A]^2 and the initial concentration of a is 0.122M.

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The charge of a chemical response is, perhaps, its maximum crucial asset because it dictates whether or not a reaction can arise all throughout an entire life. knowing the charge regulation, an expression concerning the price to the concentrations of reactants can assist a chemist to modify the response conditions to get an extra suitable rate.

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3 0
2 years ago
The following reactions can be used to prepare samples of metals. Determine the enthalpy change under standard state conditions
mamaluj [8]

Answer:

a) 62.1 kJ/mol

b) 2.82 kJ/mol

c) 270.91 kJ/mol

d) -851.5 kJ/mol

Explanation:

The enthalpy change for a reaction in standard conditions (ΔH°rxn) can be calculated by:

ΔH°rxn = ∑n*ΔH°f, products - ∑n*ΔH°f, reagents

Where n is the number of moles in the stoichiometry reaction, and ΔH°f is the enthalpy of formation at standard conditions. ΔH°f = 0 for substances formed by only a single element. The values can be found in thermodynamics tables.

a) 2Ag₂O(s) → 4Ag(s) + O₂(g)

ΔH°f, Ag₂O(s) = -31.05 kJ/mol

ΔH°rxn = 0 - (2*(-31.05)) = 62.1 kJ/mol

b) SnO(s) + CO(g) → Sn(s) + CO₂(g)

ΔH°f,SnO(s) = -285.8 kJ/mol

ΔH°f,CO(g) = -110.53 kJ/mol

ΔH°f,CO₂(g) = -393.51 kJ/mol

ΔH°rxn = [-393.51] - [-110.53 - 285.8] = 2.82 kJ/mol

c) Cr₂O₃(s) + 3H₂(g) → 2Cr(s) + 3H₂O(l)

ΔH°f,Cr₂O₃(s) = -1128.4 kJ/mol

ΔH°f,H₂O(l) = -285.83 kJ/mol

ΔH°rxn = [3*(-285.83)] - [( -1128.4)] = 270.91 kJ/mol

d) 2Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2Fe(s)

ΔH°f,Fe₂O₃(s) = -824.2 kJ/mol

ΔH°f,Al₂O₃(s) = -1675.7 kJ/mol

ΔH°rxn = [-1675.7] - [-824.2] = -851.5 kJ/mol

3 0
3 years ago
The solubility of lead(ii) chloride is 0.45 g/100 ml of solution. what is the ksp of pbcl2? 4.9 × 10-2 1.7 × 10-5 8.5 × 10-6 4.2
Artyom0805 [142]
Answer:
1.7 * 10^-5

Explanation:
1- get the number of moles of PbCl2:
number of moles = mass / molar mass
number of moles = 0.45 / 278.1 = 1.618 * 10^-3 moles

2- get the concentration of Pb2+:
molarity = number of moles of solute / volume of solution in liters
molarity = (1.618 * 10^-3) / (0.1) = 0.0162 M

3- getting concentration of Cl-:
<span>PbCl2(s) <==> Pb2+(aq) + 2Cl-(aq) 
</span>We can note that:
For a certain amount of Pb2+ formed, twice this amount of Cl- is formed.
This means that:
for 0.0162 M of Pb2+, 2*0.0168 = 0.0324 M of Cl- is formed

4- getting Ksp:
Ksp = [Pb2+][Cl-]²
Ksp = (0.0162)*(0.0324)²
Ksp = 1.7 * 10^-5

Hope this helps :)
7 0
3 years ago
To fill the valence shell, an electrically neutral, unbonded atom with atomic number 8 must add.
nikdorinn [45]

Answer:

2 electrons

Explanation:

3 0
3 years ago
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