2.Please study the figures below which illustrate the steps in the chemical reaction of fluoromethane (CH3F) with a hydroxide io
n (OH-) to form methanol (CH3OH) and a fluoride ion (F-). Each sphere represents a different type of atom according to the following key.Key: black = carbon white =hydrogen red = oxygen blue= fluorine Three molecular structures labeled A, B, and C. A. Two groups of circles. The first group is composed of a white and a red circle. To the right is a black circle in the middle with three small white and one large blue circles attached on it. B. Two groups of circles. The first group is composed of a red circle with a small white circle attached on it, attached to a black circle with three small white circles attached on it. To the right is a big blue circle. C. A group of circles. A small white circle is attached on a red circle. The red circle is attached to a black circle. Three small white circles are attached on the black circle. A big blue circle is attached on the black circle.•Write the balanced chemical equation for this reaction.•Redraw the figures above in the correct order. Be sure to label each molecule in your drawings and describe what is happening at each step of the reaction in as much detail as possible. •Draw an energy diagram to represent this reaction. Be sure to label the axes, the activation energy, and the energies of each step in the reaction.
1 answer:
1) The names of the molecules
2) Write the chemical equation
3) Balance the chemical equation
1 fluoride in the reactants and 1 fluoride in the products
1 carbon in the reactants and 1 carbon in the products
4 hydrogens in the reactants and four hydrogens in the products
1 oxygen in the reactants and 1 oxygen in the products
Since the number of atoms in the reactants is the same that the number of atoms in the products, the chemical equation is balanced.
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Answer : The standard enthalpy of formation of ethylene is, 52.4 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation reaction of will be,
The intermediate balanced chemical reaction will be,
(1)
(2)
(3)
Now we will reverse the reaction 1, multiply reaction 2 and 3 by 2 then adding all the equation, we get :
(1)
(2)
(3)
The expression for enthalpy of formation of will be,
Therefore, the standard enthalpy of formation of ethylene is, 52.4 kJ