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Evgesh-ka [11]
3 years ago
8

Fe + O2 --> FeO (unbalanced). How many mLs of O2 are needed to react with 18.0 g of Fe ? *​

Chemistry
1 answer:
worty [1.4K]3 years ago
4 0

0.161 mols.

Balance the equation first

2Fe + O2 •••••> 2FeO

Find the molar masses of the compound

2(56) + 2(16) •••••> 2(56+16)

112g + 32g •••••> 144g

Fe reacting with O2

112g of Fe reacting with 32g of O2

18g of Fe reacting with x

x= 32×18/112

x= 5.143g

Amount= mass/ molar mass

Amount= 5.143g/32g

Amount= 0.161mls

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A sample of nitrogen gas is stored in a 592.2 mL flask at 108 kPa and 10.0°C. The gas is transferred to a 750.0 mL flask at 28.9
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According to Gases law, we know, 
PV/T = Constant

So, P₁V₁/T₁ = P₂V₂/T₂

Here, P₁ = 108 kPa
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Substitute their values, 

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