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Margaret [11]
3 years ago
8

How many grams of glucose, C6H12O6, in 2.47 mole?

Chemistry
2 answers:
konstantin123 [22]3 years ago
7 0
Answer:
number of grams = 444.6 grams

Explanation:
From the periodic table, we can find that:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
mass of oxygen = 16 grams
This means that:
molar mass of C6H12O6 = 6(12) + 12(1) + 6(16) = 180 grams

Now, number of moles can be calculated using the following rule:
number of moles = mass / molar mass
Therefore:
mass = number of moles * molar mass
mass = 2.47 * 180
mass = 444.6 grams

Hope this helps :)
statuscvo [17]3 years ago
6 0
First, we need to find the atomic mass of C_{6}H_{12}O_{6}.

According to the periodic table:
The atomic mass of Carbon = C = 12.01
The atomic mass of Hydrogen = H = 1.008
The atomic mass of Oxygen = O = 16

As there are 6 Carbons, 12 Hydrogens and 6 Oxygens, therefore:
The molar mass of  C_{6}H_{12}O_{6} = 6 * 12.01 + 12 * 1.008 + 6 * 16

The molar mass of  C_{6}H_{12}O_{6} = 180.156 grams/mole

Now that we have the molar mass of  C_{6}H_{12}O_{6}, we can find the grams of glucose by using:

mass(of glucose in grams) = moles(of glucose given in moles) * molar mass(in grams/mole)

Therefore,
mass(of glucose in grams) = 2.47 * 180.156
mass(of glucose in grams = 444.99 grams

Ans: Mass of glucose in grams in 2.47 moles = 444.99 grams

-i
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Serggg [28]

Answer:

E = 19.89×10⁻¹⁶ J

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Explanation:

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speed of wave = wavelength × frequency

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7 0
2 years ago
Lastly, Snape thinks we should try one more calculation.
EleoNora [17]

Answer:

E) 0.90

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In TLC (Thin-Layer-Chromatography) retention factor RF is defined as the ratio between distance of the sample and the solvent front. RF is very important in chemistry to know the composition of any sample by comparison.

In the problem, as the sample has a distance of 0,20cm from the solvent front, the distance of the sample is:

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<em>E) 0,90</em>

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I hope it helps!

3 0
3 years ago
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