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Margaret [11]
3 years ago
8

How many grams of glucose, C6H12O6, in 2.47 mole?

Chemistry
2 answers:
konstantin123 [22]3 years ago
7 0
Answer:
number of grams = 444.6 grams

Explanation:
From the periodic table, we can find that:
mass of carbon = 12 grams
mass of hydrogen = 1 gram
mass of oxygen = 16 grams
This means that:
molar mass of C6H12O6 = 6(12) + 12(1) + 6(16) = 180 grams

Now, number of moles can be calculated using the following rule:
number of moles = mass / molar mass
Therefore:
mass = number of moles * molar mass
mass = 2.47 * 180
mass = 444.6 grams

Hope this helps :)
statuscvo [17]3 years ago
6 0
First, we need to find the atomic mass of C_{6}H_{12}O_{6}.

According to the periodic table:
The atomic mass of Carbon = C = 12.01
The atomic mass of Hydrogen = H = 1.008
The atomic mass of Oxygen = O = 16

As there are 6 Carbons, 12 Hydrogens and 6 Oxygens, therefore:
The molar mass of  C_{6}H_{12}O_{6} = 6 * 12.01 + 12 * 1.008 + 6 * 16

The molar mass of  C_{6}H_{12}O_{6} = 180.156 grams/mole

Now that we have the molar mass of  C_{6}H_{12}O_{6}, we can find the grams of glucose by using:

mass(of glucose in grams) = moles(of glucose given in moles) * molar mass(in grams/mole)

Therefore,
mass(of glucose in grams) = 2.47 * 180.156
mass(of glucose in grams = 444.99 grams

Ans: Mass of glucose in grams in 2.47 moles = 444.99 grams

-i
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Answer:

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The metals (elements in the left side of the periodic table) form positive ions, named cations, when they lose one or more valence electrons.

To depict this more clearly, consider, for example, the column 1 in the periodic table, which is the group of alkal metals: Li, Na, K, Rb, Cs, and Fr.

As you move down that column you ge the following results

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K                  4                                   1                                   K⁺

Rb                5                                   1                                   Rb⁺

Cs                6                                   1                                   Cs⁺

Fr                 7                                   1                                    Fr⁺

Then, in the last column of the previous table, you see that all the cations have the same charge, because each one is formed after lossing the same number of electrons from the neutral atom (1).

Since, as you move down the column in the periodic table, the valence electrons are in higher main energy levels, which means that the size of both the neutral atom and the and the resultant cation formed after losing the valence electron are bigger than the cation of the previous level. Hence, as a general rule, the radius of the cations of the same charge increase as you move down a colum in the periodic table.

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