Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution. (Option a)
<h3>Strength of electrolytes</h3>
- Strong electrolytes: are completely ionized in aqueous solution.
- Weak electrolytes: are partially ionized in aqueous solution.
Let's consider the ionization of ammonium hydroxide, which is a weak base.
NH₄OH ⇄ NH₄⁺ + OH⁻
Why is it considered a weak base?
a. it produces few hydroxide ions in aqueous solution. Yes, since it dissociates partially.
b. it produces few hydrogen ions in aqueous solution. No, since it does not produce hydrogen ions.
c. it does not conduct electricity in aqueous solution. No, since it conducts electricity, although poorly.
d. it will not take part in a neutralization reaction. No, since it will be neutralized by acids.
Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution.
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Answer - B Atoms in the original substances are arranged in a different way to make new substances
There are TWO atoms in one molecule of hydrogen.
Answer:
4.5 g/L.
Explanation:
- To solve this problem, we must mention Henry's law.
- Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.
- It can be expressed as: P = KS,
P is the partial pressure of the gas above the solution.
K is the Henry's law constant,
S is the solubility of the gas.
- At two different pressures, we have two different solubilities of the gas.
<em>∴ P₁S₂ = P₂S₁.</em>
P₁ = 525.0 kPa & S₁ = 10.5 g/L.
P₂ = 225.0 kPa & S₂ = ??? g/L.
∴ S₂ = P₂S₁/P₁ = (225.0 kPa)(10.5 g/L) / (525.0 kPa) = 4.5 g/L.
1) Formulas:
a) mole fraction of component 1, X1
X1 = number of moles of compoent 1 / total number of moles
b) Molar mass = number grams / number of moles => number of moles = number of grams / molar mass
2) Application
Number of moles of CaI2 = 0.400
Molar mass of water = 18.0 g/mol
Number of moles of water: 850.0 g / 18.0 g/mol = 47.22 mol
Total number of moles = 0.400 + 47.22 =47.62
Molar fraction of CaI2 = 0.400 / 47.62 = 0.00840
