The answer is heat.
To use a glue gun, it has to use heat to heat up so that it can melt the glue.
The answer is A how it react with other chemicals
❤️
Due to the other pesticides have outgrown their strength on today’s insects. All must be accompanied by mass paperwork for safety.
Answer:
Y = 92.5 %
Explanation:
Hello there!
In this case, since the reaction between lead (II) nitrate and potassium bromide is:

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

And the resulting percent yield:

Regards!