Answer:Skeletal muscle can undergo hypertrophy, as each cell gets bigger.
Explanation:
Answer:
36.75 grams of sulfuric acid will be required.
Explanation:
Moles of sodium hydroxide = 0.75 mol
![2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O](https://tex.z-dn.net/?f=2NaOH%2BH_2SO_4%5Crightarrow%20Na_2SO_4%2B2H_2O)
According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid ,then 0.75 moles of NaOH will :
sulfuric acid
Mass of 0.375 moles of sulfuric acid:
0.375 mol × 98 g/mol = 36.75 g
36.75 grams of sulfuric acid will be required.
In a precipitation reaction, one of the product formed is an insoluble precipitate.
The given reactions can be written with phases included as:
A.
: In this reaction one of the product, FeS is insoluble. Therefore, this is a precipitation reaction.
B.
: In this reaction, the product
is a solid(insoluble). So, this is a precipitation reaction too.
C.
: In this reaction, both the products are soluble. So this is not a precipitation reaction.
D.
: In this reaction, both the products are soluble. So this is not a precipitation reaction.
E.
: In this reaction, the product AgCl is a precipitate. So, it is a precipitation reaction.
Answer:
2.268 L
Explanation:
According to Ideal Gas Law, " The Volume of a given mass of gas is inversely proportional to the applied Pressure and directly proportional to applied temperature, ". Mathematically the initial and final states of gas are given as,
P₁ V₁ / T₁ = P₂ V₂ / T₂ ----------- (1)
Data Given;
P₁ = 0.998 atm
V₁ = 2.1 L
T₁ = 36 °C = 309 K
P₂ = 0.90 atm
T₂ = 28 °C = 301 K
V₂ = ??
Solving equation 1 for P₂,
V₂ = P₁ V₁ T₂ / T₁ P₂
Putting values,
V₂ = (0.998 atm × 2.1 L × 301 K) ÷ (309 K × 0.90 atm)
V₂ = 2.268 L
Answer:
"1.
buoyant or suspended in water or air.
2.not settled in a definite place; fluctuating or variable."
Explanation:
Hope this helps! :)