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QveST [7]
2 years ago
13

What is the amount of space that a gas takes up called?

Chemistry
1 answer:
trasher [3.6K]2 years ago
5 0
The answer is:Matter
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I need to know all the answers for this homework!!!!
maw [93]

1. 100 C

2. Point B to C is the ices heat capacity

3. During the points D to E the bonds of the water molecules build up enough kinetic energy to break their intermolecular bonds (not intra), which can lead to gas.

4. Between points D and E the energy is being released the energy required is equivalent along the line.

5. Between point E and D the water is converting to water (condensation)

6. Energy is being released 2260 j/g

7. Yes, but only under extreme volumetric pressures

8. D and E or B and C

9. Freezing (the water is also becoming less dense)

10. Melting or if water already, absorbtion of energy

11. released.

5 0
2 years ago
Of rational function<br>1<br>3. + 3 &lt; 0<br>3x-1<br>nctions.​
pshichka [43]

Answer:

I didn't understand questions properly. Sorry

4 0
2 years ago
You have dissolved 10 g sodium oxide in 200 ml water.calculate concentration of the solution
e-lub [12.9K]

Answer:

0.85 Molar Na2O

Explanation:

Determine the moles of sodium oxide, Na2O, in 10 grams by dividing by the molar mass of Na2O (61.98 g/mole).

 (10 g Na2O)/(61.98 g/mole) = 0.161 moles Na2O.

Molar is a measure of concentration.  It is defined as moles/liter.  A 1 M  solution contains 1 mole of solute per liter of solvent.  [200 ml water = 0.2 Liters water.]

In this case, we have 0.161 moles Na2O in 0.200 L of solvent.

 (0.161 moles Na2O)/(0.200 L) = 0.85 Molar Na2O

8 0
1 year ago
Dinitrogen trisulfide symbol
notka56 [123]
The symbol for dinitrogen trisulfide is N2S3
4 0
3 years ago
Read 2 more answers
Calculate the molarity of a solution with 233.772g sodium chloride dissolved in 2,000mL of water
LekaFEV [45]

Answer:

The molarity is 2M

Explanation:

First , we calculate the weight of 1 mol of NaCl:

Weight 1mol NaCl= Weight Na + Weight Cl= 23 g+ 35, 5 g= 58, 5 g/mol

58,5 g---1 mol NaCl

233,772 g--------x= (233,772 g x1 mol NaCl)/58,5 g= 4 mol NaCl

<em>A solution molar--> moles of solute in 1 L of solution:</em>

2 L-----4 mol NaCl

1L----x0( 1L x4mol NaCl)/4L =2moles NaCl---> 2 M

3 0
2 years ago
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