Explanation:
The reaction is as follows:
2Mg(s) + O2(g) ---> 2MgO(s)
and the researcher said that 32 g of MgO was produced.
Stoichiometry:
28 g Mg × (1 mol Mg/24.305 g Mg) = 1.15 mol Mg
15 g O2 × (1 mol O2/15.999 g O2) = 0.938 mol O2
1.15 mol Mg × (2 mol MgO/2 mol MgO) = 1.15 mol MgO
1.15 mol MgO × (40.3044 g MgO/1 mol MgO) = 46.6 g MgO
0.938 mol O2 × (2 mol MgO/1 mol O2) = 1.88 mol MgO
1.88 mol MgO × (40.3044 g MgO/1 mol MgO = 75.6 g MgO
Based on these numbers, the amount of product after the reaction is much less than expected so these results don't seem to support the law of conservation of matter.
Let x be the mass of the ore in grams such that the equation that would allow us to answer this item would be,
55 = (x)(0.243)
The value of x is calculated as,
x = 55/0.243
x = 226.337 grams
Then, solve for amount in kilograms by dividing the calculated value by 1000. This methodology will give us an answer of 0.226337. Hence, the answer is 0.226.
Yes that is definitely true
The answer is b. propel should be guided by the way of nature
Which mathematical relationship allows calculation of the equilibrium constant of a reaction if you know the standard change in Gibbs Free Energy ΔG is related to Q by the equation ΔG=RTlnQK. If ΔG < 0, then K > Q, and the reaction must proceed to the right to reach equilibrium
<h3>What is
Gibbs Free Energy?</h3>
The maximum amount of work that may be accomplished by a thermodynamically closed system at constant temperature and pressure can be determined using the Gibbs free energy (also known as Gibbs energy; symbol: displaystyle G). Additionally, it offers a prerequisite for any processes like chemical reactions that might take place in such circumstances.
The maximum amount of non-expansion work that can be taken from a closed system (one that can interchange heat and work with its surroundings but not matter) at fixed temperature and pressure is known as the Gibbs free energy change, which is measured in joules in SI. This maximum is only possible with a fully reversible method.
To learn more about Gibbs Free Energy from the given link:
brainly.com/question/9179942
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