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suter [353]
3 years ago
10

what happens to the molecule AB when it has a bond dipole and the electric field is turned on? Spin the molecule around several

times and make observations. What if the bond dipole is zero?
Chemistry
1 answer:
svet-max [94.6K]3 years ago
5 0
I have no clue?????????????????????????
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A solution of hydrochloric acid of unknown concentration was titrated with 0.10 M NaOH. If a 100.-mL sample of the HCl solution
madam [21]

<u>Answer:</u> The initial pH of the HCl solution is 3

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=100mL\\n_2=1\\M_2=0.10M\\V_2=1mL

Putting values in above equation, we get:

1\times M_1\times 100=1\times 0.10\times 1\\\\M_1=\frac{1\times 0.10\times 1}{1\times 100}=10M

1 mole of HCl produces 1 mole of H^+ ions and 1 mole of Cl^- ions

To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

[H^+]=0.001M

Putting values in above equation, we get:

pH=-\log (0.001)\\\\pH=3

Hence, the initial pH of the HCl solution is 3

6 0
3 years ago
A chemist has to prepare 250.0 mL of a 0.300 M Na2SO4(aq) solution. What mass, in grams, of sodium sulfate (formula mass 142.05
Sedbober [7]

The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g

<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
  • Volume = 250 mL = 250 / 1000 = 0.25 L
  • Molarity = 0.3 M
  • Mole of Na₂SO₄ =?

Mole = Molarity x Volume

Mole of Na₂SO₄ = 0.3 × 0.25

Mole of Na₂SO₄ = 0.075 mole

<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
  • Molar mass of Na₂SO₄ = 142.05 g/mol
  • Mole of Na₂SO₄ = 0.075 mole
  • Mass of Na₂SO₄ =?

Mass = mole × molar mass

Mass of Na₂SO₄ = 0.075 × 142.05

Mass of Na₂SO₄ = 10.65 g

Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.

Learn more about molarity:

brainly.com/question/15370276

6 0
2 years ago
Eli states that sodium phosphate is a mixture because it is composed of both sodium ions and phosphate ions.
KonstantinChe [14]

Answer is: c. It is incorrect because sodium phosphate is a compound that has a single composition.

Sodium phosphate is chemical compound composed of atoms connected with chemical bonds.

Pure substance is made of only one type of atom (element) or only one type of molecule (compound), it has definite and constant composition with distinct chemical properties.

Pure substances can be separated chemically, not physically, that is difference between pure substances and mixtures.

7 0
3 years ago
Read 2 more answers
How does the Atomic theory<br> impact our understanding of the universe?
Law Incorporation [45]

Answer:Atomic theory established that all matter is made of tiny particles, a discovery that led to amazing scientific breakthroughs in areas from modern chemistry to nuclear energy.

Explanation:Atomic theory is the scientific theory that matter is composed of particles called atoms. Atomic theory traces its origins to an ancient philosophical tradition known as atomism.

7 0
3 years ago
A 5.76 liter sample of a gas at 22.00C mL 748 torr pressure was heated to a final volume of 17.28 liters, with the pressure rema
timama [110]

Answer:

The final temperature was 612 °C

Explanation:

Charles's law relates the volume and temperature of a certain amount of ideal gas, maintained at a constant pressure, using a constant of direct proportionality. In this law, Charles says that at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

\frac{V}{T}=k

When you want to study two different states, an initial and a final one of a gas and evaluate the change in volume as a function of temperature or vice versa, you can use the expression:

\frac{V1}{T1} =\frac{V2}{T2}

In this case:

  • V1= 5.76 L
  • T1= 22 °C= 295 °K (Being 0°C=273°K)
  • V2=17.28 L
  • T2=?

Replacing:

\frac{5.76 L}{295 K} =\frac{17.28 L}{T2}

Solving:

T2 =\frac{17.28 L}{\frac{5.76 L}{295 K}}=\frac{17.28 L*295 K}{5.76 L}

T2= 885 °K = 612 °C

<u><em>The final temperature was 612 °C</em></u>

5 0
3 years ago
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