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3 years ago

What is formed by the hydrolysis of Starch?

Chemistry

1 answer:

Ymorist [56]3 years ago

3 0

Answer:

soluble starch, maltose and various dextrins.

Explanation:

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What is 1.724 L expressed in cm3?

Soloha48 [4]

1724 centimeters cubics

8 0

3 years ago

Why do higher trophic levels is most ecosystem contain fewer organisms than lower trophic levels

Alinara [238K]

Answer:

With less energy at higher trophic levels, there are usually fewer organisms as well

Explanation: Organisms tend to be larger in size at higher trophic levels, but their smaller numbers result in less biomass. Biomass is the total mass of organisms at a trophic level.

4 0

3 years ago

A 4.24 kg marble slab has the volume of 1564 cm3 What is the density in g/cm3

miskamm [114]

Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

volume of marble = 1564 cm³

1 kg = 1000 g

4.24 kg = 4240 g

mass = 4240 g

The density is

$density = \frac{4240}{1564} \\ = 2.710997442...$

We have the final answer as

Hope this helps you

7 0

3 years ago

Which resonance structure would most likely create the infrared (IR) spectrum for the equilibrium geometry calculation of SCN −

rjkz [21]

Answer:

Resonance Structures for SCN-:[S-C N]-

Resonance StructureEnergy (kJ/mol)[S-C N]--23.00[S=C=N]

3 0

3 years ago

How many grams of solid NaOH are required to prepare a 400ml of a 5N solution? show your work!

Nuetrik [128]

<u>Answer:</u> The mass of solid NaOH required is 80 g

<u>Explanation:</u>

Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

$\text{Equivalent weight}=\frac{\text{Molecular weight}}{n}$

where,

n = acidity for bases = 1 (For NaOH)

Molar mass of NaOH = 40 g/mol

Putting values in above equation, we get:

$\text{Equivalent weight}=\frac{40g/mol}{1eq/mol}=40g/eq$

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

$\text{Normality of solution}=\frac{\text{Number of gram equivalents} \times 1000}{\text{Volume of solution (in mL)}}$

Or,

$\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}$ ......(1)

We are given:

Given mass of NaOH = ?

Equivalent mass of NaOH = 40 g/eq

Volume of solution = 400 mL

Normality of solution = 5 eq/L

Putting values in equation 1, we get:

$5eq/L=\frac{\text{Mass of NaOH}\times 1000}{40g/eq\times 400mL}\\\\\text{Mass of NaOH}=80g$

Hence, the mass of solid NaOH required is 80 g

4 0

3 years ago