What is the psychoactive ingredient in alcoholic beverages? ethylene glycol methanol isopropyl alcohol ethanol?

1 answer:

7 0

The psychoactive ingredient in alcoholic beverages is Ethanol (Ethyl Alcohol).
Distilled drinks or liquors and other alcoholic drinks/beverages are produced by distilling ethanol produced by means of fermenting grain, fruit, or vegetables. Unsweetened, distilled, alcoholic drinks among other alcoholic beverages contain ethyl alcohol or ethanol as the psychoactive ingredient.

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A sample of air was collected on a day when the total atmosphere pressure was

zhuklara [117]

Answer:

1. The gas law used: Dalton's law of partial pressure.

2. Pressure of nitrogen = 331 mmHg

Explanation:

From the question given above, the following data were obtained:

Total pressure (Pₜ) = 592 mmHg

Pressure of Oxygen (Pₒ) = 261 mmHg

Pressure of nitrogen (Pₙ) =?

The pressure of nitrogen in the sample can be obtained by using the Dalton's law of partial pressure. This is illustrated below:

Pₜ = Pₒ + Pₙ

592 = 261 + Pₙ

Collect like terms

592 – 261 = Pₙ

331 = Pₙ

Pₙ = 331 mmHg

Therefore, the pressure of nitrogen in the sample is 331 mmHg

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Check the attached file for the answer.

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A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C

Mamont248 [21]

Answer:

$T_{eq}=23.85^oC$

Explanation:

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In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

$\Delta H_{Cu}=-\Delta H_{H_2O}$

Therefore the equilibrium temperature shows up as:

$m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\$