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Alexus [3.1K]
3 years ago
10

Part A Transmutation is the process of transforming one element into another through nuclear reactions. What will be the nuclide

produced when Cf-249 is bombarded with C-12? Four neutrons are also produced by the reaction. View Available Hint(s) Transmutation is the process of transforming one element into another through nuclear reactions. What will be the nuclide produced when Cf-249 is bombarded with C-12? Four neutrons are also produced by the reaction. Rf-257 Rf-260 Rf-261 Fm-261
Chemistry
1 answer:
S_A_V [24]3 years ago
5 0

<u>Answer:</u> The isotope produced after the transmutation process of Cf-249 and C-12 is _{104}^{257}\textrm{Rf}

<u>Explanation:</u>

Transmutation is defined as the process where one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.

The chemical equation for the reaction of Californium-249 nucleus with Carbon-12 nucleus follows:

_{98}^{249}\textrm{Cf}+_6^{12}\textrm{C}\rightarrow _{Z}^{A}\textrm{X}+4_0^1\textrm{n}

In a nuclear reaction, the total mass and total atomic number remains the same.

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

249 + 12 = A + 4

A = 257

<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

98 + 6 = Z + 0

Z = 104

Hence, the isotope produced after the transmutation process of Cf-249 and C-12 is _{104}^{257}\textrm{Rf}

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What is the oxidation number of cl− in the hypochlorite ion clo−?
mariarad [96]

Answer : The oxidation number of chlorine (Cl) is, (+1)

Explanation :

Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

Rules for Oxidation Numbers :

The oxidation number of a free element is always zero.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of  oxygen (O)  in compounds is usually -2, but it is -1 in peroxides.

The oxidation number of a Group 1 element in a compound is +1.

The oxidation number of a Group 2 element in a compound is +2.

The oxidation number of a Group 17 element in a binary compound is -1.

The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given compound is, ClO^-

Let the oxidation state of 'Cl' be, 'x'

x+(-2)=-1\\\\x-2=-1\\\\x=+1

Therefore, the oxidation number of chlorine (Cl) is, (+1)

5 0
3 years ago
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7 0
3 years ago
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Vedmedyk [2.9K]
The ideal gas law may be written as
p= \frac{\rho R T}{M}
where
p = pressure
ρ =density
T = temperature
M = molar mass
R = 8.314 J/(mol-K)

For the given problem,
ρ = 0.09 g/L = 0.09 kg/m³
T = 26°C = 26+273 K = 299 K
M = 1.008 g/mol = 1.008 x 10⁻³ kg/mol

Therefore
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Therefore
p = 2.2195 x 10⁵ Pa
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