<span>D) perpendicular bisector <em>I believe.
</em></span>
We have that
<span>y=2sinx-cosx
y=cosx
</span>over the interval 0≤x≤pi/2-------> 0≤x≤1.57
using a graph tool
see the attached figure
the solution in the given interval is the point (pi/4, 0.707)
the y-value of the point of intersection is 0.707 -----> √2/2
the answer is the option <span>
b. (square root of 2)/2</span>
The answer to the question is
False
I think you mean y=ab^x.
First, plug in the values of x=2 and y=24 for the first equation, and x=3 and y=48 for the second one:
24 = ab^2
48 = ab^3
divide equation 2 by equation 1:
2 = b^1
or, more simply:
2 = b
now plug b into one of the equations to get "a":
24 = a*2^2
24 = a*4
6 = a
So, the answer is y = 6(2)^x
(I think you need to specify the power of x in your answers)
7 is digit for hundred thousands and 6 is for ten thousands so the answer is 800,000