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torisob [31]
3 years ago
13

Let p: x < −3

Mathematics
2 answers:
Serhud [2]3 years ago
8 0

Answer:

B. x > 3 or x < −3

Step-by-step explanation:

We are given that,

p: x < −3

q: x > 3

Since, we know that,

The symbol v is known as 'disjunction', which is in other words represented by 'union', 'or'.

Thus, 'p ∨ q' means 'either p holds or q holds'.

Hence, we get,

'p ∨ q' is represented by 'either x <-3 or x > 3'.

i.e. 'p ∨ q' is represented by 'either x > 3 or x <-3'.

Thus, option B is correct.

Cloud [144]3 years ago
7 0

Answer:

The answer is B

Step-by-step explanation:

Ed2020

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A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a
sdas [7]

Answer:

y=-\dfrac{13}{49}x^2

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

y=ax^2+bx+c

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

-13=a(-7)^2+b(-7)+c

49a-7b+c=-13

(x,y) = (7,-13)

-13=a(7)^2+b(7)+c

49a+7b+c=-13

(x,y) = (0,0)

0=a(0)^2+b(7)+c

c=0

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13

49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13

we can solve these two equation using the elimination method, by simply adding the two equations

\quad\quad49a-7b=-13\\+\quad49a+7b=-13

------------------------------

\quad\quad 98a=-26

\quad\quad a=-\dfrac{13}{49}

Now we can plug this value of a in any of the two equations.

49a-7b=-13

49\left(-\dfrac{13}{49}\right)-7b=-13

-13-7b=-13

-7b=0

b=0

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

y=\left(-\dfrac{13}{49}\right)x^2+0x+0

y=-\dfrac{13}{49}x^2

49y=-13x^2

This our equation of the arch!

5 0
3 years ago
In the equation 5x-2=-x-20, What is the value of x?<br> a. 2<br> b. -1<br> c. -3<br> d. -2
mestny [16]

Answer:

C choice.

Step-by-step explanation:

5x - 2 =  - x - 20 \\

First, we move the same terms to the same side.

5x + x =  - 20 + 2 \\ 6x =  - 18

Then we move 6 to divide - 18.

x =  \frac{ - 18}{6}  \\ x =  - 3

7 0
3 years ago
A month of the year is chosen at random. What is the probability that the month starts with the letter Jor the letter M?
tamaranim1 [39]

Answer:

5 out of 12

5/12

January, March, May, June, July

There are three months whose name starts with the letter 'j': January, June, July

There are two months whose name starts with the letter 'm': March, May

So altogether, there are 5 months whose name starts with the letter 'j' or 'm'. So the possible outcome is 5 and total number of sample space is 12.

Therefore the required probability is: 5/12

PLEASE GIVE BRAINLYEST :)

4 0
4 years ago
Read 2 more answers
There are 30 homes in Neighborhood A. Each year, the number of homes increases by 20%. Just down the road, Neighborhood B has 45
nignag [31]
<span>Part A

</span>f(x)=30∗0.2xand<span>f(x)=45+3x</span><span>
___________________________________________________________

Part B</span>

f(x)=30+0.2(5)f(x)=45+3(5)<span>
Neighborhood A and neighborhood B both have 60 houses after 5 years
</span>
___________________________________________________________

Part C

1 year
A=36
B=48 

2 years
A=42
B=51 

3 years
A=48
B=54

4 years
A = 54
B = 57 

5 years
A = 60
B= 60
5 0
3 years ago
Read 2 more answers
Solve for k 5/8(3k+1)-1/4(7k+2)=1
lesya [120]

Answer:

<h2>k = 7</h2>

Step-by-step explanation:

\dfrac{5}{8}(3k+1)-\dfrac{1}{4}(7k+2)=1\qquad\text{multiply both sides by 8}\\\\8\!\!\!\!\diagup^1\cdot\dfrac{5}{8\!\!\!\!\diagup_1}(3k+1)-8\!\!\!\!\diagup^2\cdot\dfrac{1}{4\!\!\!\!\diagup_1}(7k+2)=8\cdot1\\\\5(3k+1)-2(7k+2)=8\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(5)(3k)+(5)(1)+(-2)(7k)+(-2)(2)=8\\\\15k+5-14k-4=8\qquad\text{combine like terms}\\\\(15k-14k)+(5-4)=8\\\\k+1=8\qquad\text{subtract 1 from both sides}\\\\k=7

3 0
3 years ago
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