Question

a gas in a container with a fixed volume was originally at a pressure of 317kpa and a temperature of 154k. what is the new pressure in atm if the temperature is increased to 235k​

Answer 1

Hello!

The answer is: 4.77atm

Why?

Since there's a fixed volume, we can use the the Gay-Lussac's Law which stablish a relation between the pressure and the temperature:

$\frac{P}{T}=k$

P is the volume of the gas

t is the temperature of the gas

k is the proportionality constant

We also have the following equation:

$\frac{P1}{T1}=\frac{P2}{T2}$

Where:

$P2=\frac{P1*T2}{T1}=\frac{317kPa*235K}{154K}=483.73kPa$

We are asked to find the pressure in atm, so we must convert 483.73kPa to atm:

$1kPa=0.009869atm$

Then,

$483.733kPa*\frac{0.009869atm}{1kPa}=4.77atm$

Have a nice day!