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vazorg [7]
4 years ago
7

Compare wave A with wave B correctly in relation to amplitude.

Chemistry
2 answers:
Anni [7]4 years ago
7 0
<span>Wave A will have a higher pitch than wave B.. This is not true becasue b has the higher PITCH becasue it's closer together.

Wave B will have a lower pitch than wave A... This basically A but worded differently. 

Wave A will have a louder sound than wave B... This is CORRECT becasue it's louder the waver are bigger, so it's louder. But it has a lower pitch, 2 different things. 

Wave B will have a louder sound than wave A. False..</span><span />
ioda4 years ago
6 0

The correct answer for this question would be : B) <u>Wave A will be louder than wave B</u>

<u></u>

<u></u>

<u></u>

<u></u>

<u></u>

<h2>GOOD LUCK, HOPE I HELPED!!!</h2><h2 />
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Calculation: If you have a pH of 5.5 for a weak acid with a pKa of 4.76, then is there more A- or more HA in the solution? Expla
devlian [24]

Answer:

lets set the ratio -A/HA as R:

pH = pKa + log(R,10) => pKa + log10(R)

pH = 5.5

pKa = 4.76

R => 10^(pH - 4.76)

10^(pH - 4.76) => 5.4954

Given R (-A/HA) a number bigger than 1, then the concentration of  -A is bigger than HA

Explanation:

6 0
3 years ago
Read 2 more answers
The equation for photon energy, E, is E=hc/λ
Leni [432]

Answer:

The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m

Explanation:

The wavelength is defined for every periodic wave, that is, for the type of wave that repeats itself with exactly the same shape every given interval of time. It is the distance between two points from which the wave repeats.

Radiation is the emission, propagation and transfer of energy in any medium in the form of electromagnetic waves or particles.

The energy carried by electromagnetic radiation travels by waves. This energy is transmitted grouped in small "quanta" of energy called photons. The energy of a photon is measured in Joules (J) and is

E=\frac{h*c}{wavelength}

Being:

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  • h= 6.626×10⁻³⁴ J⋅s (Planck's constant)
  • c = 2.99×10⁸ m/s (the speed of light)
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and replacing:

3.92*10^{-19}J =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s}   }{wavelength}

you get:

wavelength =\frac{6.626*10^{-34}J.s*2.99*10^{8}\frac{m}{s}   }{3.92*10^{-19}J}

wavelength= 5.054*10⁻⁷ m

<u><em>The wavelength, λ, of a photon that has an energy of E = 3.92×10⁻¹⁹ J is 5.054*10⁻⁷ m</em></u>

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3 years ago
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Dipole, less electronegativity,  higher electronegativity

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