Compare wave A with wave B correctly in relation to amplitude.
2 answers:
You might be interested in
Answer:
not aromatic
Explanation:
Cyclopropene -
as the compound is is made to lose a proton , and gains a negative charge on its ring ,
Now, The ring can become aromatic or anti - aromatic depending on the number of π electrobns ,
According to Huckel 's rule ,
The cyclic compounds with ( 4n+2 ) π electrons , where , n = 0, 1, 2, 3 ... , are considered to be aromatic in nature ,
And the cyclic compounds with ( 4n ) π electrons , where , n = 1, 2, 3 ... , are considered to be anti - aromatic in nature.
Now, for the cyclopropene structure , the number of π electron are equal to 4 , 2 from the double bond and 2 from the negative charge .
Therefore , the compound becomes not aromatic or anti - aromatic .
Answer:
c. Compound 2 is more acidic because its conjugate base is more resonance stabilized
Explanation:
You haven't told us what the compounds are, so let's assume that the formula of Compound 1 is HCOCH₂OH and that of Compound 2 is CH₃COOH.
The conjugate base of 2 is CH₃COO⁻. It has two important resonance contributors, and the negative charge is evenly distributed between the two oxygen atoms.
CH₃COOH + H₂O ⇌ CH₃COO⁻ + H₃O⁺
The stabilization of the conjugate base pulls the position of equilibrium to the right, so the compound is more acidic than 1.
