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3 years ago

Compare wave A with wave B correctly in relation to amplitude.

Chemistry

2 answers:

Anni [7]3 years ago

7 0

<span>Wave A will have a higher pitch than wave B.. This is not true becasue b has the higher PITCH becasue it's closer together.

Wave B will have a lower pitch than wave A... This basically A but worded differently.

Wave A will have a louder sound than wave B... This is CORRECT becasue it's louder the waver are bigger, so it's louder. But it has a lower pitch, 2 different things.

Wave B will have a louder sound than wave A. False..</span><span />

ioda3 years ago

6 0

The correct answer for this question would be : B) <u>Wave A will be louder than wave B</u>

<u></u>

<h2>GOOD LUCK, HOPE I HELPED!!!</h2><h2 />

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What is the mass in grams of 9.45*10^24 molecules of methanol (CH3OH)?

Angelina_Jolie [31]

Number of moles:

1 mole ---------- 6.02x10²³ molecules
? moles --------- 9.45x10²⁴ molecules

1 x ( 9.45x10²⁴) / 6.02x10²³ =

9.45x10²⁴ / 6.02x10²³ => 15.69 moles of CH3OH

Therefore:

Molar mass CH3OH = 32.04 g/mol

1 mole ------------ 32.04 g
15.69 moles ----- mass methanol

Mass methanol = 15.69 x 32.04 / 1 => 502.7076 g

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3 years ago

Write the proper word equation to express the following chemical reaction: 4Fe (s) + 3Sn(NO3)4 (aq) arrow 4Fe(NO3)3 (aq) + 3Sn (

Lapatulllka [165]

The word equation for this reaction is:

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3 years ago

What is the pH of a solution that is 0.40 M NaBrO and 0.50 M HBrO (hypobromous acid) (Ka for HBrO = 2.3 x 10^-9)

Pie

Answer

pH=8.5414

Procedure

The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.

pH = pKa + log₁₀ ([A⁻] / [HA])

Where

pH = acidity of a buffer solution

pKa = negative logarithm of Ka

Ka =acid disassociation constant

[HA]= concentration of an acid

[A⁻]= concentration of conjugate base

First, calculate the pKa

pKa=-log₁₀(Ka)= 8.6383

Then use the equation to get the pH (in this case the acid is HBrO)

$pH=8.6383+\log_{10}(\frac{0.40\text{ M}}{0.50\text{ M}})=8.5414$

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1 year ago

Which change will cause the greatest increase in the rate of reaction for this chemical reaction? 8Zn(s) + S8(s) 8ZnS(s) A. addi

Rus_ich [418]

I found another question like this. Someone answered "The best answer to this question is adding a catalyst.

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3 years ago

Read 2 more answers

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tresset_1 [31]

Answer:

9.8

Explanation:

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