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ArbitrLikvidat [17]
3 years ago
8

HEY ITS E AGAIN HELP ITS A TEST

Chemistry
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

i am not 100% shure but the wind speed has little to effect it so a and b are not the answer so i think the answer is D

Explanation:if i got this wrong im sorry it has bin a wile since i answered a question like this.

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The compound ncl3 is nitrogen trichloride, but alcl3 is simply aluminum chloride. why
AveGali [126]
The answer to this question would be:
NCl3 is a molecular compound (two or more nonmetals), and therefore in its name prefixes indicate the number of each type of atom. so NCl3 is nitrogen trichloride<span>.
</span><span>The compound AlCl3 is an ionic compound (metal and nonmetal), and therefore does not require prefixes. so AlCl3 is aluminum chloride.
</span><span>
Both of nitrogen and chlorine is nonmetal, but aluminum is metal. Metal with nonmetal will make an ionic compound that doesn't need prefixes.</span>
5 0
4 years ago
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Which of the following describe chemical properties?
VLD [36.1K]
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4 0
3 years ago
1. Define the units for molarity. Page |152 Exp. 14 pH and Solutions Pre Lab Questions (1 of 1) 2. A solution contains 5.25 gram
Ne4ueva [31]

Answer:

1. mol/L

2. 0.120 M

Explanation:

1. Molarity is equal to the moles of solute divided by the liters of solution. The units of molarity are mol/L.

2.

Step 1: Given data

  • Mass of sodium chloride (solute): 5.25 g
  • Volume of solution (V): 750.0 mL = 0.7500 L

Step 2: Calculate the moles of solute (n)

The molar mass of NaCl is 58.44 g/mol.

n = 5.25 g × 1 mol/58.44 g = 0.0898 mol

Step 3: Determine the molarity of the solution

We will use the definition of molarity

M = n/V

M = 0.0898 mol / 0.7500 L = 0.120 M

7 0
3 years ago
Calculate thr number of photons having a wavelength of 10.0 μm required to produce 1.0 kJ of energy.
ddd [48]
Ok so first you need to figure out the energy of ONE photon with that wavelength. Using E=hc/lambda, you get E= 1.99 * 10^-20 J/photon. Now, how many photons do you need to add up to get to one kilojoule=1000 joules? 1000J / (1.99 * 10^-20 J/photon) = approximately 5 * 10^22 photons hope this helps
4 0
3 years ago
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Is this correct? <br>plssssssssss help me
Irina-Kira [14]
This is not correct.
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3 years ago
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