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ArbitrLikvidat [17]
3 years ago
8

HEY ITS E AGAIN HELP ITS A TEST

Chemistry
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

i am not 100% shure but the wind speed has little to effect it so a and b are not the answer so i think the answer is D

Explanation:if i got this wrong im sorry it has bin a wile since i answered a question like this.

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If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

4 0
3 years ago
Name 2 separate technique in separating iodine crystal and iron filings​
KonstantinChe [14]

One is through sublimation, where the mixture is heated and iodine gets converted into gaseous form, leaving behind the iron fillings.

The other is to get a magnet near the mixture and all the iron fillings get attracted to it while iodine will be left over

5 0
3 years ago
What type(s) of bonding would be expected for each of the following materials: brass (a copper-zinc alloy), rubber, barium sulfi
mr_godi [17]

The force of attraction that results in holding of atoms or ions together in a molecule or crystal is said be bonding.  Bond formation can take place by either attraction or transfer of electrons. There are single, double, and triple bonds.  There are many types of bonding namely:

Covalent (sharing of electrons takes place).

Ionic (transfer of electrons takes place).

Metallic (ionized atoms of metals and the sea of electrons around them).

  • Brass (a copper-zinc alloy)

Brass is an alloy of metal that is copper and zinc. Hence, the metallic bonding is present in the brass.

  • Rubber

It is a polymer whose monomer unit is isoprene, which is a covalent compound. The isoprene units are attached in repeated units to form rubber by covalent bonding.

  • Barium sulfide (BaS)

Due to the large electronegativity difference between barium and sulfur, barium sulfide is an ionic compound. Thus, ionic bonding is present in barium sulfide.

  • Solid xenon

Only xenon atoms are present in solid xenon which are interacted by weak Van der Waal's interactions.

  • Bronze

Bronze is an alloy of metal that is copper and tin. Hence, the metallic bonding is present in the brass.

  • Nylon

It is a polymer whose monomer unit is caprolactam, which is a covalent compound. The caprolactam units are attached in repeated units to form nylon by covalent bonding.

  • Aluminum phosphide (AlP)

Aluminum phosphide is a covalent compound and thus involves covalent bonding.

7 0
3 years ago
Which of the following statements is true?
Anna007 [38]

Answer:

C. Lithium is most easily oxidized of the metals listed on the activity series and therefore it will most easily give electrons to metal cations

Explanation:

"Lithium" is a type of alkali metal that has a "single valence electron." Since it is a reactive element, it easily gives up an electron when it is combined with other elements. Such giving up of electron is meant to create compounds or bonds.

Among the common metals listed, "lithium" is the most easily oxidized. This means that it donates its electrons immediately. Such combination makes it exist as a<em> "cation"</em> or <em>"positively-charged."</em>

So, this explains the answer.

6 0
3 years ago
Explain what Happens at the saturation point when adding salt to water at room temperature.
lorasvet [3.4K]

Answer:

See below  

Step-by-step explanation:

You won't see much happening. The solution is saturated, so the salt will fall to the bottom of the container and sit there. It will not dissolve.

However, at the atomic level, Na⁺ and Cl⁻ ions are being pulled from the surface of the crystals and going into solution as hydrated ions. At other places, Na⁺ and Cl⁻ ions are returning to the surface of the crystals.

The process is

NaCl(s) ⇌ Na⁺(aq) + Cl⁻(aq)

The rates of the forward and reverse processes are equal, so you see no net change.

6 0
3 years ago
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