3 years ago

NH3

Chemistry

1 answer:

soldier1979 [14.2K]3 years ago

4 0

Answer:

First one is: ammonia

Second one is: calcium hydroxide

Explanation:

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What is the mass in grams of 2.50 mol of ammonia vapor, NH3?

Crank

Molar mass:-

$\\ \tt\longmapsto 14+3(1)=17g/mol$

Now

$\\ \tt\longmapsto Given\:mass=No\;of\:moles\times Molar\;mass$

$\\ \tt\longmapsto Given\:mass=17(2.5)$

$\\ \tt\longmapsto Given\:mass=42.5g$

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3. A 31.2-g piece of silver (s = 0.237 J/(g · °C)), initially at 277.2°C, is added to 185.8 g of a liquid, initially at 24.4°C,

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Answer:

$Cp_{liquid}=2.54\frac{J}{g\°C}$

Explanation:

Hello,

In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

$Q_{Ag}=-Q_{liquid}$

That in terms of the heat capacities, masses and temperature changes turns out:

$m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})$

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

$Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}$

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