Answer:
I. a, c, f and h
II. e
III. b, d, g and i
IV. i
Explanation:
I. Chemical symbols are simple abbreviations used to represent various elements or compound. They consist entire of alphabet.
For the diagram given above, the labelled parts which represent chemical symbol are: a, c, f and h
II. Coefficients are numbers written before the chemical symbol of elements or compound.
For the diagram given above, the labelled part which represent Coefficient is: e
III. Number of atoms of element present in a compound is simply obtained by taking note of the numbers written as subscript in the chemical formula of the compound.
For the diagram given above, the labelled part which represent the number of atoms of the element are: b, d, g and i
IV. When no number is written as subscript in the formula of the element in the compound, it means the element has just 1 atom in the compound.
For the diagram given above, the labelled part which indicates that only 1 atom of the element is present is: i
Answer:
The answer is Letter B The car travel at a constant veloc
Answer:
im pretty sure the answer is c please mark me brainliest
Answer:
Explanation:
2.5 g of He = 2.5 / 4 mole
= .625 moles
9 g of oxygen = 9/32
= .28 mole of oxygen
C_p of He = 3/2 R
C_p of O₂ = 5/2 R
A ) Initial thermal energy of He = 3/2 n R T
= 1.5 x .625 x 8.32 x 300
= 2340 J
Initial thermal energy of O₂ = 5/2 n R T
= 2.5 x .28 x 8.32 x 620
= 3610.88 J
B ) If T be the equilibrium temperature after mixing
gain of heat by helium
= n C_p Δ T
= .625 x 3/2 R x ( T - 300 )
Loss of heat by oxygen
n C_p Δ T
= .28 x 5/2 R x ( 620 - T )
Loss of heat = gain of heat
.625 x 3/2 R x ( T - 300 ) = .28 x 5/2 R x ( 620 - T )
1.875 T- 562.5 = 868- 1.4 T
3.275 T = 1430,5
T = 436.8 K
Thermal energy of He
= 1.5 x .625 x 8.32 x 436.8
= 3407 J
thermal energy of O₂
= 2.5 x .28 x 8.32 x 436.8
= 2543.92 J
C )
Heat energy transferred
= .28 x 5/2 R x ( 620 - T )
= .28 x 5/2 x 8.32 x ( 620 - 436.8 )
1066.95 J
Heat will flow from O₂ to He
Final temperature is 436.8 K
In a block and tackle, some friction in the pulleys will reduce the mechanical advantage of the machine. To include friction in a calculation of the mechanical advantage of a block and tackle, divide the weight of the object being lifted by the weight necessary to lift it.
Hope this helps
