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ArbitrLikvidat [17]
3 years ago
15

Falling Faster

Physics
1 answer:
Daniel [21]3 years ago
3 0
In a vacuum they would fall at the same speed, but since it is only off the empire State building, the hammer would fall first

Gravity
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What would a series circuit be used for?
igor_vitrenko [27]

Answer:

C

Explanation:

a series circuit would be an odd choice to power a battery or light a lamp when a direct would be much more efficient, and it's not converting types of energy, so C is the best possible answer

6 0
2 years ago
What is lenz law?<br>What is galvanometer?​
yulyashka [42]

Answer:

Lenz's law, in electromagnetism, statement that an induced electric current flows in a direction such that the current opposes the change that induced it. This law was deduced in 1834 by the Russian physicist Heinrich Friedrich Emil Lenz (1804–65).

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2 years ago
Which of the following is true about a planet orbiting a star in uniform circular motion? A. The direction of the velocity vecto
Luda [366]
<span>As it is uniform circular motion therefore speed is constant. Therefore we can rule out option B. Also in circular motion the direction of velocity vector changes therefore velocity can't be constant. Therefore option B is incorrect as well. Also centripetal acceleration is always towards the center so option D is wrong as well. That implies option A is correct.</span>
4 0
3 years ago
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Based on the replacement reaction, what would the products of the reaction be?
cricket20 [7]

Answer:

\rm Be(OH)_2 and \rm (NH_4)_2 SO_4. The missing ion would be \rm OH^{-}.

Explanation:

In a double replacement reaction, two ionic compounds exchange their ions to produce two different ionic compounds.

In this question, the two ionic compounds are:

  • \rm BeSO_4, and
  • \rm NH_4 OH.

In particular,

  • \rm BeSO_4 is made up of \rm Be^{2+} ions and \rm {SO_4}^{2-} ions, while
  • \rm NH_4 OH is made up of \rm {NH_4}^{+} ions and \rm OH^{-} ions.

In a binary ionic compound, cations (positive ions) can only bond to anions (negative ions.)

  • \rm Be^{2+} is a cation. In \rm BeSO_4, \rm Be^{2+} was bounded \rm {SO_4}^{2-} anions. During the reaction, it bonds with \rm OH^{-} anions to produce \rm Be(OH)_2.
  • \rm {NH_4}^{+} is also a cation. In \rm NH_4 OH, \rm {NH_4}^{+} was bounded to \rm OH^{-} ions. During the reaction, it bonds with \rm {SO_4}^{2-} anions to produce \rm (NH_4)_2 SO_4.

Hence, the two products will be \rm Be(OH)_2 and \rm (NH_4)_2 SO_4.

Note that charges on the ions must balance. For example, a \rm Be^{2+} ion carries twice as much charge as an \rm {NH_4}^{+} ion. As a result, each \rm Be^{2+} ion would bond with twice as many \rm OH^{-} ions as \rm {NH_4}^{+} would in \rm NH_4 OH.

4 0
3 years ago
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imagine that a brown horse and a white horse cross of producing Offspring who Coke is made of some brown hairs and some white ha
Zolol [24]
This pattern would be a codominant pattern.
4 0
3 years ago
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