Explanation:
Sorry but I don't Understand question
The fraction of radioisotope left after 1 day is
, with the half-life expressed in days
Explanation:
The question is incomplete: however, we can still answer as follows.
The mass of a radioactive sample after a time t is given by the equation:

where:
is the mass of the radioactive sample at t = 0
is the half-life of the sample
This means that the mass of the sample halves after one half-life.
We can rewrite the equation as

And the term on the left represents the fraction of the radioisotope left after a certain time t.
Therefore, after t = 1 days, the fraction of radioisotope left in the body is

where the half-life
must be expressed in days in order to match the units.
Learn more about radioactive decay:
brainly.com/question/4207569
brainly.com/question/1695370
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Momentum = mass x velocity
m=7.3kg
v=20 m/s
momentum= 7.3(20) = 146 kg m/s
Answer:

Explanation:
the relation between current, voltage and resistance in an electrical circuit is given by Ohm's law:

where V is the voltage, I is the current and R is the resistance. In this problem, the current is I=2 A, the voltage is V=120 V, therefore we can arrange the previous equation and find the resistance:

Water vapor and carbon dioxide