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Vladimir79 [104]
3 years ago
10

Lila is a track and field athlete. She must complete four laps around a circular track. The track itself is a 400 meter track an

d it took her 6 minutes total to complete. Which best describes her speed and velocity? (There are 60 seconds in 1 minute.) A. Her speed is 4.4 m/s, and her velocity is 0 m/s. B.Her speed is 1.1 m/s, and her velocity is 0 m/s. C.Her speed is 0 m/s, and her velocity is 2400 m/s. D. Her speed is 4.4 m/s, and her velocity is 4.4 m/s.
Physics
1 answer:
trapecia [35]3 years ago
6 0

Answer: A. Her speed is 4.4 m/s, and her velocity is 0 m/s.

Explanation: i took the test on edgenuity

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A compact car has a mass of 1380 kg . Assume that the car has one spring on each wheel, that the springs are identical, and that
astraxan [27]

Answer:

A) k=34867.3384\ N.m^{-1}

B) \omega'\approx84\ Hz

Explanation:

Given:

mass of car, m=1380\ kg

A)

frequency of spring oscillation, f=1.6\ Hz

We knkow the formula for spring oscillation frequency:

\omega=2\pi.f

\Rightarrow \sqrt{\frac{k_{eq}}{m} } =2\pi.f

\sqrt{\frac{k_{eq}}{1380} } =2\times \pi\times 1.6

k_{eq}=139469.3537\ N.m^{-1}

Now as we know that the springs are in parallel and their stiffness constant gets added up in parallel.

<u>So, the stiffness of each spring is (as they are identical):</u>

k=\frac{k_{eq}}{4}

k=\frac{139469.3537}{4}

k=34867.3384\ N.m^{-1}

B)

given that 4 passengers of mass 70 kg each are in the car, then the oscillation frequency:

\omega'=\sqrt{\frac{k_{eq}}{(m+70\times 4)} }

\omega'=\sqrt{\frac{139469.3537}{(1380+280)} }

\omega'\approx84\ Hz

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