What is the equation of the following graph?

Mathematics

1 answer:

nignag [31]3 years ago

6 0

Answer:

${y}^{2} = 24x$

Step-by-step explanation:

This is horizontal parabola.

It has a directrix at x=-6.

The vertex is (0,0).

The focus is (6,0)

The equation of this parabola is of the form

${y}^{2} = 4px$

Where (p,0) is the focus

By comparison, p=6

Therefore the equation of the parabola is

${y}^{2} = 4 \times 6x$

This implies that

${y}^{2} =2 4 x$

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Duke Energy reported that the cost of electricity for an efficient home in a particular neighborhood of Cincinnati, Ohio, was $1

Gnoma [55]

Answer:

Step-by-step explanation:

a. H0: μ ≤ 104 Ha: μ > 104

Assuming the data leads to the rejection of the null hypothesis, we would conclude that there is no sufficient statistical evidence to prove that the cost of electricity for an efficient home in a particular neighborhood of Cincinnati, Ohio, was $104 per month.

b. The type error in this situation would be rejecting the null hypothesis when it is actually true. Rejecting the fact that the cost of electricity for an efficient home in a particular neighborhood of Cincinnati, Ohio, was $104 per month when it was actually true.

c. Type II error in this case would be failing to reject the null when it is false. Failing to reject the fact that the cost of electricity for an efficient home in a particular neighborhood of Cincinnati, Ohio, was $104 per month when it is actually not true.

The consequences for these errors might be disastrous including sueing of the accuser party etc.

8 0

2 years ago

(3x-5)/(x-5)>=0 <br> How do I get the answers for this problem?

Diano4ka-milaya [45]

$\frac{3x-5}{x-5}$ > 0

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: $\frac{3x-5}{x-5}$ = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = $\frac{5}{3}$
Sixth, from the values of x above, we have these 3 intervals to test:
x < $\frac{5}{3}$
$\frac{5}{3}$ < x < 5
x > 5
Seventh, pick a test point for each interval.

1. For the interval x < $\frac{5}{3}$ :
Let's pick x - 0. Then, $\frac{3x0-5}{0-5}$ > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval $\frac{5}{3}$ < x < 5:
Let's pick x = 2. Then, $\frac{3x2-5}{2-5}$ > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, $\frac{3x6-5}{6-5}$ > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < $\frac{5}{3}$ and x > 5

Answer: x < $\frac{5}{3}$ and x > 5

3 0

3 years ago

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Softa [21]

Answer:

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