1 astronomical unit (1AU) or 150 000 000 km's (1.5 x<em>10^9</em> km). In SI units this is 10^12 meters
The direction of an electric field at any point is the direction that a
small positive charge would want to move if it were located there.
We know that like charges repel. So the electric field around a
positive charge always points away from it.
The electric field at a point to the left of the positive charge Q
points away from Q, toward the left. A small positive charge
located there would want to get farther away from Q, and it
would try to move farther left.
It rises up the the surface when the surrounding rock is less dense
Answer:
Distance
Speed = ----------------
Time
Distance/Displacement
1.5m/s = ------------------------------------------
10s
Distance
1.5m/s × 10 = --------------------- × 10
10s
(Get rid of the fraction by multiplying it by the denominator in this case 10)
15m = Distance
Distance and Displacement are almost the same thing regarding this question. But watch out when you doing other questions and when you have initial velocity and initial time.
Displacement is 15m.