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Mnenie [13.5K]
3 years ago
12

Explain nanotechnology. Its advantages, disadvantages with examples or application? ​

Physics
1 answer:
Volgvan3 years ago
7 0

Answer:

PURPOSE

This information bulletin clarifies the Department of Building and Safety’s (LADBS) requirement

relating to the equipment (product) and wiring approval as delineated in Sections 110.2, 110.3,

93.0401, 93.0402, and 93.0403 of the 2017 edition of the City of Los Angeles Electrical Code (LAEC).

DEFINITIONS

Approved - Acceptable to authority having jurisdiction. {California Electrical Code (CEC), Article 100}

Authority Having Jurisdiction – An organization, office, or individual responsible (i.e., LADBS

Electrical Testing Laboratory or Inspection) for enforcing the requirements of a code or standard, or

for approving equipment, material, an installation, or a procedure. (CEC, Article 100)

Equipment - A general term, including material, fittings, devices, appliances, luminaires, apparatus,

machinery, and the like used as part of, or in connection with, an electrical installation. (CEC, Article

100)

Identified - Recognizable as suitable for the specific purpose, function, use, environment, application,

and so forth, where described in particular code requirement. (CEC, Article 100)

Labeled - Equipment or material to which has been attached a label, symbol, or other accepted

identifying mark (i.e., embossed laboratory logo) of a recognized (approved) testing agency (see

definition) and concerned with product evaluation, that maintains periodic inspection of production of

labeled equipment or materials, and by whose labeling the manufacturer indicates compliance with

recognized national safety standards (see definition). (CEC, Article 100)

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Push with force of 1N

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Where does the kinetic energy come fromwhen you roll down a hill?
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The refractive index n of transparent acrylic plastic (full name Poly(methyl methacrylate)) depends on the color (wavelength) of
Novosadov [1.4K]

Answer:

The angle between the blue beam and the red beam in the acrylic block is  

 \theta _d  =0.19 ^o

Explanation:

From the question we are told that

     The  refractive index of the transparent acrylic plastic for blue light is  n_F  =  1.497

     The  wavelength of the blue light is F  =  486.1 nm  =  486.1 *10^{-9} \ m

    The  refractive index of the transparent acrylic plastic for red light is  n_C  =  1.488

       The  wavelength of the red light is C =  656.3 nm  = 656.3 *10^{-9} \  m

    The incidence angle is  i  =  45^o

Generally from Snell's law the angle of refraction of the blue light  in the acrylic block  is mathematically represented as

       r_F =  sin ^{-1}[\frac{sin(i) *  n_a }{n_F} ]

Where  n_a is the refractive index of air which have a value ofn_a =  1

So

     r_F =  sin ^{-1}[\frac{sin(45) *  1 }{ 1.497} ]

      r_F  =  28.18^o

Generally from Snell's law the angle of refraction of the red light in the acrylic block is mathematically represented as

       r_C =  sin ^{-1}[\frac{sin(i) *  n_a }{n_C} ]

Where  n_a is the refractive index of air which have a value ofn_a =  1

So

     r_C =  sin ^{-1}[\frac{sin(45) *  1 }{ 1.488} ]

      r_F  =  28.37^o

The angle between the blue beam and the red beam in the acrylic block

     \theta _d  =  r_C  - r_F

substituting values

       \theta _d  = 28.37 -  28.18

       \theta _d  =0.19 ^o

 

4 0
3 years ago
Use the Venn Diagram to compare and contrast solar and lunar eclipses.
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5 0
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What is a positive effect of increased carbon dioxide within the carbon cycle?
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