9514 1404 393
Answer:
y = 3.02x^3 -5.36x^2 +5.68x +8.66
Step-by-step explanation:
Your graphing calculator (or other regression tool) can solve this about as quickly as you can enter the numbers. If you have a number of regression formulas to work out, it is a good idea to become familiar with at least one tool for doing so.
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If you're trying to do this by hand, the x- and y-values give you 4 equations in the 4 unknown coefficients.
a·1^3 +b·1^2 +c·1 +d = 12
a·3^3 +b·3^2 +c·3 +d = 59
a·6^3 +b·6^2 +c·6 +d = 502
a·8^3 +b·8^2 +c·8 +d = 1257
Solving this by elimination, substitution, or matrix methods is tedious, but not impossible. Calculators and web sites can help. The solutions are a = 317/105, b = -75/14, c = 1193/210, d = 303/35. Approximations to these values are shown above.
Answer: The points of the images are (9,10), (15,6), (6,4) and the image is not a rigid motion because the shape changes in side.
Step-by-step explanation:
Since it gives you the scale factor then find they coordinates by multiplying the coordinates by the scare factor.
A(3,5) → (3*3,5*2) → (9,10)
B( 5,3) → (5*3, 3*2) → (15,6)
C ( 2,3)→ (2*3, 2*2)→ ( 6,4)
Call the smaller of the two odds = n
Call the next number in the sequence = n + 2
n*(n +2) = 782 Remove the brackets.
n^2 + 2n = 782 Subract 782 from both sides.
n^2 + 2n - 782 = 0 We are going to have to factor this.
Discussion
This problem can't be done the way it is written. The product of an odd integer with another odd integer is and odd integer. There are no exceptions to this. So you need to give a number that has two factors very near it's square root for this question to work.
For example, you could use 783, (which factors) instead of 782 .
Solve
n^2 + 2n - 783 = 0
(n + 29)(x - 27) = 0
<u>Solution One</u>
n - 27 = 0
n = 27
The two odd consecutive integers are 27 and 29.
<u>Solution Two</u>
n + 29 = 0
n = - 29
The two solution integers are -29 and - 27 Notice that - 29 is smaller than - 27.
Answer:
Step-by-step explanation:
As you can observe in the image attached, the line that best fits passes through point B and C. That means we can use those point to find the slope of such line.
Where 
and 
So, the slope of the line that best fits is -11, approximately.
Now, we use the point-slope formula to find the equation.
Therefore, the line that best fits is approximately.
Remember, when we estimate a line for some data on a scatterplot, we are calculating an approximation, that's why we also said "approximately", because the line is an approximation where the majority of point meet.
