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lutik1710 [3]
3 years ago
14

Which of the following is the graph of y=-4√x

Mathematics
2 answers:
Svetllana [295]3 years ago
7 0
It appears that no graph photos have been uploaded, however, I have pasted the graph for the equation Y= -4 sqrt x.
https://www.symbolab.com/solver/step-by-step/y%3D-4%5Csqrt%7Bx%7D
Rom4ik [11]3 years ago
6 0

Answer:

Please see the attachment for graph.

Step-by-step explanation:

We are a given a equation and need to graph it.

It is square root function. We make table of x and y and then plot the points on graph and join the points.

We will take some random values of x and then find the value of y corresponding to the value of x.

For x=1, Put x=1 into equation

y=-4\sqrt{1}=-4

For x=4, Put x=4 into equation

y=-4\sqrt{4}=-8

For x=9, Put x=9 into equation

y=-4\sqrt{9}=-12

Table of x and y

     x          y

     1         -4

    4         -8

    9         -12

Now we plot the points on graph and join the points.

Please see the attachment for graph.


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An automobile manufacturer sold 30,000 new cars, one to each of 30,000 customers, in a certain year. The manufacturer was intere
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       The costumers who bought a new car on a certain year.
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B) The 32.5% probability refers to customers having issues with the power doors locks among the costumers who had problems, it does not consider the customers who did not have any problem or those who had problems after the first 5000 miles.

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3 years ago
1. Write the equation of the piece-wise function graphed below​.
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Problem 4

<h3>Answer:</h3>

f(x) = \begin{cases}2x+4 \text{ if } x < 1\\x-3 \text{ if } x \ge 1\end{cases}

------------------

Work Shown:

The left line goes through (-2,0) and (0,4)

The slope of this line is

m = (y2-y1)/(x2-x1)

m = (4-0)/(0-(-2))

m = (4-0)/(0+2)

m = 4/2

m = 2

The y intercept is b = 4

Since m = 2 and b = 4, this means y = mx+b turns into y = 2x+4. This portion is only done when x < 1. Note the open circle at the endpoint of this portion. So we do not include x = 1 as part of this piece.

---

The line on the right side goes through (1,-2) and (2,-1)

Slope

m = (y2-y1)/(x2-x1)

m = (-1-(-2))/(2-1)

m = (-1+2)/(2-1)

m = 1/1

m = 1

The y intercept is b = -3. You can see this if you extend the line until it crosses the y axis.

Alternatively, plug in (x,y) = (1,-2) and m = 1 into y = mx+b to find that b = -3

So y = mx+b turns into y = 1x+(-3) or just y = x-3

We combine both parts to end up with f(x) = \begin{cases}2x+4 \text{ if } x < 1\\x-3 \text{ if } x \ge 1\end{cases}

This is only graphed when x \ge 1 (note the closed or filled in circle for the endpoint of this portion).

===================================================

Problem 5

Answer:

<h3>f(x) = \frac{1}{2}|x+3| is the absolute value function</h3><h3>while this is the piecewise function</h3>

f(x) = \begin{cases}-\frac{1}{2}(x+3) \text{ if } x < -3\\\frac{1}{2}(x+3) \text{ if } x \ge -3\end{cases}\\

------------------

Work Shown:

y = |x| .... parent function

y = |x+3| ... shift 3 units to the left

y = (1/2)*|x+3| .... vertically compress by factor of 1/2

f(x) = (1/2)*|x+3|

------

Break that down into a piecewise function

when x < -3, then y = -(1/2)(x+3)

when x \ge -3, then y = (1/2)(x+3)

I'm using the rule that y = |x| turns into y = -x when x < 0 and y = x when x \ge 0

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