3 years ago

Use the velocity vs time graph to analyze the motion of the object.

Physics

1 answer:

arsen [322]3 years ago

7 0

Explanation:

the object has constant velocity for 2 seconds and it get a constant accelration (2ms-2)

You might be interested in

A runner whose mass is 54 kg accelerates from a stop to a speed of 7 m/s in 3 seconds. (A good sprinter can run 100 meters in ab

Darya [45]

Answer:

a. $F=126N$

b. $E_K=1323J$

Explanation:

Given:

$m=54kg$

$v=7 m/s$

$t= 3s$

The runner force average to find given the equations

$F=m*a$

$a=\frac{v}{t}$

$F=m*\frac{v}{t}=54kg*\frac{7m/s}{3s}$

$F=126N$

Work done by the system by this force so

$W=F*d$

$W=E_K$

$E_K=\frac{1}{2}*m*v^2$

$E_K=\frac{1}{2}*54kg*(7m/s)^2$

$E_K=1323J$

6 0

2 years ago

Which of the following criteria can help Linda classify gases as greenhouse gases?

liubo4ka [24]

gas molecules having at least one oxygen atom

7 0

3 years ago

Read 2 more answers

Where is the most energy transferred in a food web

Paladinen [302]

Answer:

The first trophic level of the food chain has the most energy.

8 0

3 years ago

Which equation would you use to solve the following problem? An object is moved 29 m with a force of 289 N. What is the work don

Ksivusya [100]

Work, scientifically speaking, is done when a force is applied to an object which consequently moves the object at a certain direction. Work in formula, is force multiplied with distance.
W = F x d

4 0

3 years ago

What is the net work doneon the object over the distance shown?

GuDViN [60]

$A)F_0d$

Explanation

If you graph the force on an object as a function of the position of that object, then the area under the curve will equal the work done on that object, so we need to find the area under the function to find the work

Step 1

find the area under the function.

Area:

$\text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red}$ $\begin{gathered} \text{the area of a rectangle is given by} \\ A_{rec}=lenght\cdot widht \\ \text{and} \\ \text{the area of a triangle is given by:} \\ A_{tr}=\frac{base\cdot height}{2} \end{gathered}$

$\begin{gathered} \text{Area}=rec\tan gle_{green}+triangle_{gren}-triangle_{red} \\ \text{replace} \\ \text{Area}=(F_0\cdot d)+\frac{(F_0\cdot d)}{2}-\frac{(F_0\cdot d)}{2} \\ \text{Area}=(F_0\cdot d) \\ Area=F_0d \end{gathered}$

therefore, the answer is

$A)F_0d$

I hope this helps you

4 0

1 year ago