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blsea [12.9K]
4 years ago
8

What is electric force ​

Physics
1 answer:
jenyasd209 [6]4 years ago
6 0

Answer:

An electric force is exerted between any two charged objects. Objects with the same charge, both positive and both negative, will repel each other, and objects with opposite charges, one positive and one negative, will attract each other

Explanation:

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Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 50 kg ball tra
Tasya [4]

The formula for kinetic energy is  KE = (1/2) (mass) (speed²)

== The 50 kg ball traveling at 10 m/s has <em>some</em> kinetic energy.  

== A 50 kg ball traveling at 20 m/s would be moving at double the speed.  So it would have (2)² = <em>4 times as much</em> kinetic energy.

== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = <em>1/4 as much</em> kinetic energy.

== A 50 kg <u>person</u> falling at 10 m/s would have <em>exactly the same</em> amount of kinetic energy as the 50 kg <u>ball</u> traveling at 10 m/s.

5 0
3 years ago
Read 2 more answers
All protons in a vacuum have the same<br> 1) Speed<br> 2) Wavelength<br> 3) Energy<br> 4) Frequency
IRISSAK [1]
4). Frequency


I had a class on it.
5 0
3 years ago
A student boils water in a can and puts the hot can carefully in very icy water. The can immediately crushes due to the change i
hammer [34]

Answer:

By elimination I know it's not CGL and I know it's not Charle's Law.

Gay-Lussac's law states the pressure of a a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant. I think it's Gay-Lussac's Law.

Boyle's law states that pressure of a gas tends to increase as the volume of the container decreases which I got from a google search because I didn't know what it was.

CGL is the combined formula of all of these laws by the way

Charle's law is just gas expands when heated.

Gay-Lussac's is the best answer choice in my opinion

8 0
4 years ago
9. A force does 50 ) of work on an object at rest with a mass of 4 kg. Which of the following is the final velocity of the objec
e-lub [12.9K]

Answer:

5 m/s

Explanation:

Work is force times distance.

W = Fd

Force is mass times acceleration.

W = ma d

Acceleration is change in velocity over change in time.

W = m Δv / Δt d

Distance over time is average velocity.

W = m Δv v_avg

W = m (v − v₀) (v + v₀) / 2

W = m (v² − v₀²) / 2

Plugging in values:

50 J = 4 kg (v² − (0 m/s)²) / 2

25 m²/s² = v²

v = 5 m/s

4 0
4 years ago
horizontal circular platform rotates counterclockwise about its axis at the rate of 0.919 rad/s. You, with a mass of 73.5 kg, wa
VARVARA [1.3K]

Answer:

The total angular momentum is 292.59 kg.m/s

Explanation:

Given that :

Rotation of the horizontal circular platform \omega = 0.919 rad/s

mass of the platform (m) = 90.7 kg

radius (R) = 1.91 m

mass of the poodle m_p = 20.5 kg

Your mass  m' = 73.5 kg

speed v = 1.05 m/s with respect to the platform

V_p = \frac{1.05}{2} \ m /s \\ \\ = 0.525  \ m /s  \\  \\r = \frac{R}{2}

r = 0.955

Mass of the mutt m_m = 18.5 kg

r' = \frac{3}{4} \ R

Your angular momentum is calculated as:

Your angular velocity relative to the platform is \omega' = \frac{v}{R}  = \frac{1.05}{1.91 } = 0.5497 \ rad/s

Actual \ \omega_y = \omega - \omega ' = (0.919 - 0.5497) \ rad/s = 0.3693 \ rad/s

I_y = m'R^2 = 73.5 *1.91^2= 268.14 \ kgm^2

L_Y = I_y*\omega_y= 268.14*0.3683= 98.76 \ kg.m/s

For poodle :

Relative \ \ \omega' = \frac{V_p}{R/2} = 0.550 \  rad/s

Actual \omega_p = \omega - \omega' =  0.919 -0.550 = 0.369 \ rad/s

I_p = m_p(\frac{R}{2} )^2  = 20.5(\frac{1.91}{2} )^2 = 18.70 \ kgm^2

L_p = I_p *\omega_p = 18.70*0.369 = 6.9003 \  kgm/s

I_M = m_m(\frac{3}{y4} R)^2 = 18.5 (\frac{3}{4} 1.91)^2 = 37.96 \  kgm^2

L_M = I_M \omega = 37.96 * 0.919= 34.89 \ kg.m/s

Disk I = \frac{mr^2}{2} =  \frac{90.7*1.91^2}{2}= 165.44 \ kgm^2

L_D = I \omega = 165.44*0.919 =152.04 \ kg.m/s

Total angular momentum of system is:

L = L_D +L_Y+L_P+L_M

= (152.04 + 98.76 + 6.9003 + 34.89) kg.m/s

= 292.59 kg.m/s

6 0
4 years ago
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