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mihalych1998 [28]
3 years ago
10

Which of the following explains how Hahn, Strassman, and Meitner tried to

Chemistry
2 answers:
attashe74 [19]3 years ago
5 0

Answer is: A. They opposed the use of energy released during nuclear fission for military purposes.

Hahn, Strassmann and Meitner were not engaged in nuclear weapons research during World War II.

Otto Hahn (1879 - 1968) became a passionate campaigner against the use of nuclear energy as a weapon.

Hahn and Strassmann discovered nuclear fission (nuclear fission of uranium in 1939).

larisa [96]3 years ago
4 0

Answer:

A. They opposed the use of energy released during nuclear fission for military purposes.

Explanation:

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Write a word or phrase begining with each letter of the word CHANGE that describes changed you have observed in everyday objects
ipn [44]
C – coming to senses and finally realized that everything is dynamic and I should learn to invest into knowing what of these changes are right or wrong and being

H – hopeful that someday, these changes will actually make sense and that all of these questions and confusions will be answered in the right time and the right place. But whatever happens, I must learn to

A – adapt from the different things I see everyday, If the world changes for its betterment or for its worse, then I too, should change as well to go with the flow. However, keep in mind to

N – never leave the small things behind because these things when summed up actually what make sense of everything and could possibly answer the

G – growing dynamics of the world and its inhabitants. Throughout all this, it is always important to
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E-educate yourself, that when the change will finally take effect on you, you will be ready.</span>
6 0
2 years ago
Question 5
Kobotan [32]

This hypothesis can be further substantiated by having different concentrations of acid and the same mass of limestone.

<h3>Rate of reaction</h3>

Though the question is incomplete, we must try to answer it the much we can. Recall that a hypothesis is a tentative explanation for an observation which is subject to empirical verification.

We know that the rate of reaction depends on the concentration of the acid. This hypothesis can be further substantiated by having different concentrations of acid and the same mass of limestone.

Learn more about rate of reaction: brainly.com/question/8592296

7 0
2 years ago
1. Which of the combinations in the lab activity had indications that a chemical change occured? Defend your argument with evide
ArbitrLikvidat [17]

Answer:The green growing on the penny of copper and the rust forming on the nail of iron are chemical changes. Boiling away salt water, scraping iron filings from a mixture of sand with a magnet, and breaking a rock with a hammer, are physical changes.

Explanation:

4 0
3 years ago
Kc for the reaction N2O4 &lt;=&gt; 2NO2 is 0.619 at 45 degrees C If 50.0g of N2O4 is introduced into an empty 2.10L container, w
Nadya [2.5K]

Answer:

p(N2O4) = 0.318 atm

p(NO2) = 7.17 atm

Explanation:

Step 1: Data given

Kc = 0.619

Temperature = 45.0 °C

Mass of N2O4 = 50.0 grams

Volume = 2.10 L

Molar mass N2O4 = 92.01 g/mol

Step 2: The balanced equation

N2O4 ⇔ 2NO2

Step 3: Calculate moles N2O4

Moles N2O4 = 50.0 grams / 92.01 g/mol

Moles N2O4 = 0.543 moles

Step 4: The initial concentration

[N2O4] = 0.543 moles/2.10 L = 0.259 M

[NO2]= 0 M

Step 5: Calculate concentration at the equilibrium

For 1 mol N2O4 we'll have 2 moles NO2

[N2O4] = (0.259 -x)M

[NO2]= 2x

Step 6: Calculate Kc

Kc = 0.619=  [NO2]² / [N2O4]

0.619 = (2x)² / (0.259-x)

0.619 = 4x² / (0.259 -x)

x = 0.1373  

Step 7: Calculate concentrations

[N2O4] = (0.259 -x)M = 0.1217 M

[NO2]= 2x = 0.2746 M

Step 8: The moles

Moles = molarity * volume

Moles N2O4 = 0.1217 M * 2.10  = 0.0256 moles

Moles NO2 = 0.2746 M * 2.10 = 0.577 moles

Step 9: Calculate partial pressure

p*V = n*R*T

⇒ with p = the partial pressure

⇒ with V = the volume = 2.10 L

⇒ with n = the number of moles

⇒ with R = the gas constant = 0.08206 L*atm/mol*K

⇒ with T = the temperature = 45 °C = 318 K

p = (nRT)/V

p(N2O4) = (0.0256 *0.08206 * 318)/ 2.10

p(N2O4) = 0.318 atm

p(NO2) = (0.577 *0.08206 * 318)/ 2.10

p(NO2) = 7.17 atm

6 0
3 years ago
Why is the mass of the third subatomic particle ignored?
dmitriy555 [2]

Answer: The mass of electrons is mostly ignored because electrons are extremely small compared to neutrons and protons.

Explanation: A proton is about 1,836 times the size of an electron.

On the periodic table, the atomic number for each element can be found. This number is found by measuring the weight of 6.02 x 10^23 atoms of the element in grams. Electrons aren't ignored when finding exact math, but for the sake of simplification high school teachers will generally have you only count the number of protons and neutrons when calculating the mass of atoms.

3 0
1 year ago
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