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mihalych1998 [28]
3 years ago
10

Which of the following explains how Hahn, Strassman, and Meitner tried to

Chemistry
2 answers:
attashe74 [19]3 years ago
5 0

Answer is: A. They opposed the use of energy released during nuclear fission for military purposes.

Hahn, Strassmann and Meitner were not engaged in nuclear weapons research during World War II.

Otto Hahn (1879 - 1968) became a passionate campaigner against the use of nuclear energy as a weapon.

Hahn and Strassmann discovered nuclear fission (nuclear fission of uranium in 1939).

larisa [96]3 years ago
4 0

Answer:

A. They opposed the use of energy released during nuclear fission for military purposes.

Explanation:

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I need help with this!
san4es73 [151]

Answer:

2.68 cm^3

Explanation:

Density= Mass/Volume

so...

8.96 g/cm^3 = 24.01 g/ V

and then u solve so it would be 2.68 cm ^3

((:

3 0
3 years ago
An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respective
katovenus [111]

Answer:

The new partial pressures after equilibrium is reestablished:

PCl_3,p_1'=6.798 Torr

Cl_2,p_2'=26.398 Torr

PCl_5,p_3'=223.402 Torr

Explanation:

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At equilibrium before adding chlorine gas:

Partial pressure of the PCl_3=p_1=13.2 Torr

Partial pressure of the Cl_2=p_2=13.2 Torr

Partial pressure of the PCl_5=p_3=217.0 Torr

The expression of an equilibrium constant is given by :

K_p=\frac{p_1}{p_1\times p_2}

=\frac{217.0 Torr}{13.2 Torr\times 13.2 Torr}=1.245

At equilibrium after adding chlorine gas:

Partial pressure of the PCl_3=p_1'=13.2 Torr

Partial pressure of the Cl_2=p_2'=?

Partial pressure of the PCl_5=p_3'=217.0 Torr

Total pressure of the system = P = 263.0 Torr

P=p_1'+p_2'+p_3'

263.0Torr=13.2 Torr+p_2'+217.0 Torr

p_2'=32.8 Torr

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At initail

(13.2) Torr     (32.8) Torr                        (13.2) Torr

At equilbriumm

(13.2-x) Torr     (32.8-x) Torr                        (217.0+x) Torr

K_p=\frac{p_3'}{p_1'\times p_2'}

1.245=\frac{(217.0+x)}{(13.2-x)(32.8-x)}

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished:

p_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr

p_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr

p_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr

6 0
3 years ago
A sample of iron absorbs 67.5 j of heat upon which the temperature of the sample increases from 21.5 °c to 28.5 °c. if the speci
asambeis [7]
Q = mcΔθ

67.5 = m x 0.45 x (28.5 - 21.5)

M = 67.5 / 3.15
= 21.4 g
3 0
3 years ago
Read 2 more answers
Anita did not make the track team this year, and she feels really disappointed and upset. What question would most likely redire
Allushta [10]

Answer:

Anita did not make the track team this year, and she feels really disappointed and upset. What question would most likely redirect her thinking and provide a solution?

Why did this terrible thing happen to me?

What other sports can I try this spring?

Why does everything I attempt go wrong?

Why did Karen get on the team but I didn't?

Answer - What other sports can I try this spring?

Explanation:

Failures and successes are part of our daily lives as humans. It can be very challenging for one to accept his or her failures and bring oneself above it.

when failure occur, the best way to reverse the negative impacts it brings is to move forward and decide on what next to do.  

The actions that must be taken in the processes should be quite productive enough to bring back the results one desired.

When the effects of failures prove irreversible, one would then give the mind a diversion and help his or herself think their way though the failure that was encountered.

4 0
3 years ago
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
lesya692 [45]
<span>Mol is the unit of amount of substance. It is equal to 6.02 x 10^23 molecules. Now, One mol of Sodium chloride (NaCl) contains 6.022x 10^23 molecules of NaCl. Also, the number atoms of both Na (sodium) and Cl (chlorine) will be equal. Similatly, One mol of Aluminium Chloride (AlCl3) contains 6.022x 10^23 molecules of (AlCl3) but the ratio of Al and Cl atoms will be 1:3</span>
7 0
3 years ago
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