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DedPeter [7]
3 years ago
12

Hector claims that a single sodium ion and a single oxygen ion do not bond together to form a stable binary ionic compound. Is h

e correct? Why or why not?
A Hector is incorrect. The two ions have opposite charges, so they will bond together in a binary ionic compound.
B Hector is incorrect. The two ions have more than eighteen protons, so they will bond together in a binary ionic compound.
C Hector is correct. The sum of the charges of the two ions must be zero in order for them to form a stable ionic compound.
D Hector is correct. The sum of the protons of the two ions must be divisible by eight in order for them to form a stable ionic compound.
Chemistry
2 answers:
levacccp [35]3 years ago
8 0

Answer:

C

Explanation:

Looking at the periodic table, we can see that sodium is in group 1, so a sodium ion would be Na⁺, with a charge of +1. Oxygen is in group 16, so an oxygen ion would be O²⁻, with a charge of -2.

A compound formed only by a single sodium ion and a single oxygen ion would thus have a charge of -1, and in order to have a stable ionic compound its charge must be zero.

Anuta_ua [19.1K]3 years ago
5 0

Answer: A Hector is incorrect. The two ions have opposite charges, so they will bond together in a binary ionic compound.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Electronic configuration of sodium:

[Na]=1s^22s^22p^63s^1

Sodium atom will loose two electrons to gain noble gas configuration and form sodium cation with +1 charge.

[tex][Na^{+}]=1s^22s^22p^63s^0[/tex]

Electronic configuration of oxygen:

[O]=1s^22s^22p^4

Oxygen atom will gain one electron to gain noble gas configuration and form oxide ion with -2 charge.

[O^{2-}]=1s^22s^22p^6

Here sodium is having an oxidation state of +1 called as Na^+ cation and oxide O^{2-} is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Na_2O.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

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Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)
Natali [406]

Answer:

<u />

  • <u>a) 1.44g</u>

<u />

  • <u>b) 77.3%</u>

<u />

Explanation:

<u>1. Chemical balanced equation (given)</u>

       NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)

<u>2. Mole ratio</u>

1molNaOH(aq):1molKHP(s)

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

<u />

<u>3. Find the number of moles in 72.14 mL of the base</u>

    Molarity=\text{number of moles of solute}/\text{volume of solution in liters}

    \text{Volume of solution}=72.14mL=0.07214liters

     \text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol

<u>4. Find the number of grams of KHP that reacted</u>

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

  • mass = number moles × molar mass = 0.007055mol × 204.23g/mol
  • mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

<u>5. Find the percentage of KHP in the sample</u>

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

  • % = (mass of substance / mass of sample) × 100

  • % = (1.4408g/ 1.864g) × 100 = 77.3%
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3 years ago
Guys someone shared their notes with me how should I thank them
Dvinal [7]
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2 years ago
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The right line is a 90° clockwise rotation of the left line about the origin. Click the 90° clockwise button. Are these lines th
inessss [21]

Answer:

Switch the coordinates and change the sign of the second one by multiplying it by negative 1.

Explanation:

Here are some examples and a more general way to understand the problem.

Consider the point (1,1), a 90 degree rotation clockwise about the origin would move it into the 4th quadrant.

The new point is (1,-1) , similarly (-4,2)-> (2,4), (-4,3)-> (3,4)

We take a point p= (x,y) the the result of rotation p 90 clockwise about the orgin is a new point p'=(x',y')= (-y, x). .

In the case of p=(1,0) the new point is p'= (0, -1)

One can use a matrix where the first row is cos(a), sin(a) and the second row is

-sin(a) cos(a) for any clockwise rotation of a degrees about the origin.

If we let a=90 degrees we have

[0 1] as the first row and [-1 0] as the second row. So the matrix is:

|0 1|

|-1 0|

Call that matrix M

So a point p= (x,y) can be multiplied by M as follows Mp=p' where p' is the rotated point.

If p=(-4,2) then Mp

is M(-4,2) which after matrix multiplication means x'=0*-4+1*2=2 and y'=-1*-4+0*2=4

So p'=(2,4)

Try it with (1,0)

x'=1*0+0*1=0

y'=-1*1+0*1=-1

so p'=(0,-1) and (1,0)->(0,-1)

How about the point on the y axis (0,1), it should go to the point (1,0)

0*1+1*1=1 and -1*0+0*1 gives you the pont (1,0) ( we don't see the negative sign because -0 is just 0)

7 0
3 years ago
When a connector is marked with "al-cu," the connector is suitable for use with copper, copper-clad aluminum, and aluminum condu
IgorLugansk [536]

When connectors are marked with a combination of metals, it can be used as a connector of one of the metals or an alloy of the two metals. So in this case, since the marking is “Al – Cu” where Al is aluminium and Cu is copper, therefore the answer is:

<span>Yes, it is suitable for use with copper, copper-clad aluminum, and aluminum conductors.</span>

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3 years ago
An isotope of carbon has 8 neutrons. What is the correct hyphenated symbol for this isotope?
Rom4ik [11]

Answer:

Carbon-14 or C-14

Explanation:

Since the isotope is a carbon isotope, it means the the atomic number of the isotope is 6.

The atomic number of an element is the proton number.

Therefore, the isotope has a proton number of 6

Now we need to obtain the mass number of isotope in order to write the symbol of the isotope. This is illustrated below:

Mass number = Proton +Neutron

Proton = 6

Neutron = 8

Mass number = 6 + 8

Mass number = 14

Therefore, the symbol of the isotope is carbon-14 or C-14

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