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serious [3.7K]
2 years ago
15

A solution has a [OH-] of 1 x 10^-12 M. What is the [H3O+] of the solution?

Chemistry
1 answer:
Yakvenalex [24]2 years ago
4 0
First, lets find the pOH
pOH=-log[OH] ----> pOH=-log[1x10^-12] ----->pOH=12
Now we can find the pH
14-12=2
Now we can use the pH=-log[H3O] to find the hydrogen ion concentration
2=-log[H3O] ------>[H3O]=1.0 x 10^-2
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What is the final temperature of a sample of water if 12.15J of energy is added to 475g of water at an initial temperature of 20
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Answer:

The final temperature of water is <u>20.5061 °C.</u>

Explanation:

Let the final temperature of water be 'x'.

Given:

Heat added to water is, Q_{in}=12.15\ J

Initial temperature of water is, T=20.5\ \°C

Mass of water is, m=475\ g

Now, heat  is added to water and its temperature is increased. The temperature is increased because water absorbs all the heat.

Heat absorbed by water is given as:

Q_{abs}=mc(x-T) where 'c' is specific heat capacity of water and its value is equal to 4.186 J/g °C.

Now, plug in the given values and simplify.

Q_{abs}=475\times4.186\times(x-20.5)\\Q_{abs}=1988.35(x-20.5)

Now, from law of conservation of energy, we know that:

Heat absorbed by water = Heat added to water

Q_{abs}=Q_{in}\\1988.35(x-20.5)=12.15\\x-20.5=\frac{12.15}{1988.35}\\x-20.5=0.0061\\x=20.5+0.0061=20.5061\ \°C

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Part D

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