A solution has a [OH-] of 1 x 10^-12 M. What is the [H3O+] of the solution?

1 answer:

4 0

First, lets find the pOH
pOH=-log[OH] ----> pOH=-log[1x10^-12] ----->pOH=12
Now we can find the pH
14-12=2
Now we can use the pH=-log[H3O] to find the hydrogen ion concentration
2=-log[H3O] ------>[H3O]=1.0 x 10^-2

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1,62 mol of N2= mass/ 28
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