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Oduvanchick [21]
3 years ago
5

In an experiment designed to determine the concentration of Cu 2 ions in an unknown solution, you need to prepare 100 mL of 0.10

M CuSO4 as your stock solution. How many grams of CuSO4(s) should you use
Chemistry
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

1.6 grams

Explanation:

We need to prepare 100 mL (0.100 L) of a 0.10 M CuSO₄ solution. The required moles of CuSO₄ are:

0.100 L × 0.10 mol/L = 0.010 mol

The molar mass of CuSO₄ is 159.61 g/mol. The mass corresponding to 0.010 moles is:

0.010 mol × (159.61 g/mol) = 1.6 g

We should use 1.6 grams of CuSO₄.

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According to the chart of specific heats, which material requires the most heat to raise its temperature from 10°C to 30°C?
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The material which requires the most heat to raise its temperature from 10°C to 30°C is oil.

<h3>What is the formula to calculate absorbed heat?</h3>

The formula which we used to calculate the amount of involved heat in relation with specific heat is:

Q = mcΔT, where

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Among the given materials, specific heat of oil is highest than other materials so will require maximum absorbed heat.

Hence, oil requires the most heat.

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Explanation:

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The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles
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<u>Answer:</u> The expression for equilibrium constant is K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

<u>Explanation:</u>

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

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aA+bB\rightleftharpoons cC+dD

The expression for K_c is given as:

K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical reaction:

2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)

The expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}

The concentration of solid is taken to be 0.

So, the expression for K_{eq} is given as:

K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}

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3 years ago
What is the name of the molecule shown below?
xxTIMURxx [149]

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