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alexandr1967 [171]
3 years ago
12

Plzzzzz helpppppp meeeee I am dooo confused

Chemistry
1 answer:
Ksju [112]3 years ago
7 0

Answer:

I think the person is not move

Explanation:

b/c the net force is zero............. 100 w + 100 E

............... 100+(-100 = 0

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Molecular and empirical formulas
shepuryov [24]

Answer:

See below

Explanation:

Molecular formula  ( just write down all of the elements )   C 4 H4 O4

Empiracle formual    CHO

"Molecular formulas tell you how many atoms of each element are in a compound, and empirical formulas tell you the simplest or most reduced ratio of elements in a compound"

7 0
2 years ago
How did music change during medieval, renaissance and baroque eras​
Vilka [71]

Answer:

usage of trills and vibrato

Explanation:

earlier music used trills while later styles would use vibrato.

7 0
3 years ago
How many salt and water would you use to prepare 10% salt solution?
tatuchka [14]

Answer:

We can make 10 percent solution by volume or by mass. A 10% of NaCl solution by mass has ten grams of sodium chloride dissolved in 100 ml of solution. Weigh 10g of sodium chloride. Pour it into a graduated cylinder or volumetric flask containing about 80ml of water.

Explanation:

have a good day

4 0
3 years ago
What does an arrow in a chemical equation show?
kobusy [5.1K]

Answer:

A chemical equation consists of the chemical formulas of the reactants (on the left) and the products (on the right). The two are separated by an arrow symbol (“→” usually read aloud as “yields”). ... The equation also identifies that all the compounds are in the gaseous state.

Explanation:

6 0
3 years ago
Read 2 more answers
300 moles of sodium nitrite are needed for a reaction. the solution is 0.450 m. how many ml are needed?
miv72 [106K]

Answer:

\boxed{\text{667 000 mL}}

Explanation:

\text{Molar concentration} = \dfrac{\text{moles}}{\text{litres}}\\\\c = \dfrac{n}{v}

Data:

c = 0.450 mol·L⁻¹

n = 300 mol

Calculation:

\begin{array}{rcl}0.450 & = & \dfrac{300}{V}\\\\0.450V& = & 300\\\\V & = & \dfrac{300}{0.450}\\\\V & = & \text{667 L} =\textbf{667 000 mL}\end{array}\\\text{The volume of solution needed is }\boxed{\textbf{667 000 mL}}

4 0
3 years ago
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