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kramer
4 years ago
7

Are microbe multicellular

Physics
2 answers:
Aleks04 [339]4 years ago
8 0
"Some microbiologists also include viruses, but others consider these as nonliving. Most microorganisms are unicellular, but this is not universal, since somemulticellular<span> organisms are microscopic. Some unicellular protists and </span>bacteria<span>, like Thiomargarita namibiensis, are macroscopic and visible to the naked eye."</span>
maksim [4K]4 years ago
6 0

Microbes are unicellular

 

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If the atoms that share electrons have an unequal attraction for the electrons is called
Karolina [17]

If the atoms that share electrons have an unequal attraction for electrons, the bond is called a Polar covalent bond.

<h3><u>Explanation:</u></h3>

A covalent chemical bond is formed in case of two different non-metals when one or more electron pairs are shared between bonding atoms. A difference in electronegativity of subsequent atoms of a covalent bond leads to formation of a small net charge around nucleus of each atom, pulling the shared electrons to one side of the bond, to the nucleus which has higher electronegativity.

HCl is an example of polar covalent bond and the HCl bond has Chlorine more electronegative. The bonding electrons are more close to Cl than H and hence Cl is partially negatively charged than H which has partial positive charge (HCl bond : H^{+} - Cl^{-}). When electrons shared in a covalent bond have equal attraction, the bond is a Non-Polar covalent bond.

6 0
4 years ago
PHYSICS HELP PLEASE!! MUST SHOW MATH WORK!!
SVETLANKA909090 [29]

<u>Answer:</u>

1) Distance traveled by bird = 403 meter

2)Average speed = 1.66 km /hour

3) Zcceleration = 2 m/s^2

<u>Explanation:</u>

1)  Distance traveled = Speed * Time taken = 31 * 13 = 403 meter.

2)  Average speed = Total distance covered / Time taken for that distance to cover.

    Total distance covered = 2+0.5+2.5 = 5 km

    Time taken = 3 hours

     Average speed = 5/3 = 1.66 km /hour

3)    Acceleration is defined as the rate of change of velocity, so acceleration a = change in velocity/time.

  Change in velocity = 14 - 6 = 8 m/s

   Time = 4 seconds

   So acceleration = 8 / 4 = 2 m/s^2

6 0
3 years ago
The critical angle for a certain air-liquid surface is 47.7°. What is the index of refraction of the liquid? Round to the neares
KengaRu [80]

Answer:

The index of refraction of the liquid is 1.35.

Explanation:

It is given that,

Critical angle for a certain air-liquid surface, \theta_1=47.7^{\circ}

Let n₁ is the refractive index of liquid and n₂ is the refractive index of air, n₂ =1

Using Snell's law for air liquid interface as :

n_1\ sin\theta_1=n_2\ sin(90)

n_1\ sin(47.7)=1

n_1=\dfrac{1}{sin(47.7)}

n_1=1.35

So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.

5 0
3 years ago
Indica si las siguientes acciones son el resultado de un efecto estatico o dinamico de una fuerza.
Oduvanchick [21]

Answer:

Sabemos por definición que la fuerza es lo que es capaz de producir cambios o deformaciones en un cuerpo y a esto se denomina efecto estático y cuando la alteración ejerce movimiento o reposo se denomina efecto dinámico, con esta base resolvemos que:

-estirar un muelle: efecto estatico

- devolver una volea: efecto dinámico

- aplastar la plastilina: efecto estático

- empujar el carro del supermercado: efecto dinámico

- inflar un globo: efecto estático

8 0
3 years ago
Can you answer this math homework? Please!
kap26 [50]

\large \mathfrak{Solution : }

9. An object which is in circular motion (moving along a circle) is said to be accelerating because it changes it's direction constantly even if it is moving with a constant speed. cuz acceleration is change in either magnitude or direction of an object with respect to time.

therefore, it's still acceleration as change in direction with time.

10. Average speed of an object can be calculated by dividing the total distance covered by an object by time taken to cover that distance.

i.e

  • \boxed{speed =  \dfrac{distance}{time} }

it can be re- arranged to find the distance as :

  • \boxed{distance = speed \times time}

  • time =  \dfrac{distance}{speed}

11. speed = 20 m/s : conversion into km/h

distance covered : 4 km = 4000 m

  • time =  \dfrac{distance}{speed}

  • t =  \dfrac{4000}{20}

  • t =  200 \:  \: sec

time taken = 200 seconds

12. let's use the first equation of motion to find the acceleration :

  • v = u + at

  • 50 = 80 + 120a

  • 50 - 80 = 120a

  • a =  \dfrac{ - 30}{120}

  • a = -   \dfrac{1}{4} m/s {}^{2}

  • - 0.25 \:  \: m/s {}^{2}
3 0
3 years ago
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