The mass of 5 kg on the Earth has a greater weight than the mass of 20 kg on the moon.
Explanation:
The weight of an object is given by
![W=mg](https://tex.z-dn.net/?f=W%3Dmg)
where
m is the mass of the object
g is the acceleration of gravity
On the Earth, the acceleration due to gravity is
![g=9.8 m/s^2](https://tex.z-dn.net/?f=g%3D9.8%20m%2Fs%5E2)
So a mass of m = 5 kg on the Earth would weigh
![W=mg=(5)(9.8)=49 N](https://tex.z-dn.net/?f=W%3Dmg%3D%285%29%289.8%29%3D49%20N)
On the moon, the acceleration due to gravity is
![g=1.6 m/s^2](https://tex.z-dn.net/?f=g%3D1.6%20m%2Fs%5E2)
So a mass of m = 20 kg on the Moon would weigh
![W=mg=(20)(1.6)=32 N](https://tex.z-dn.net/?f=W%3Dmg%3D%2820%29%281.6%29%3D32%20N)
So, the mass of 5 kg on the Earth has a greater weight than the mass of 20 kg on the moon.
Learn more about forces and weight:
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Answer:
1.40 N
Explanation:
The magnitude of the frictional force is given by:
![F=\mu N](https://tex.z-dn.net/?f=F%3D%5Cmu%20N)
where
is the coefficient of friction
N is the magnitude of the normal reaction
The coefficient of friction for this problem is
. The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so
![N=65 N+52 N=117 N](https://tex.z-dn.net/?f=N%3D65%20N%2B52%20N%3D117%20N)
Therefore, the frictional force is
![F=\mu N=(0.012)(117 N)=1.40 N](https://tex.z-dn.net/?f=F%3D%5Cmu%20N%3D%280.012%29%28117%20N%29%3D1.40%20N)
The alpha line in the Balmer series is the transition from n=3 to n=2 and with the wavelength of λ=656 nm = 6.56*10^-7 m. To get the frequency we need the formula: v=λ*f where v is the speed of light, λ is the wavelength and f is the frequency, or c=λ*f. c=3*10^8 m/s. To get the frequency: f=c/λ. Now we input the numbers: f=(3*10^8)/(6.56*10^-7)=4.57*10^14 Hz. So the frequency of the light from alpha line is f= 4.57*10^14 Hz.
The Force Is Pushing The Object The Opposite Way It Is In Motion