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sukhopar [10]
4 years ago
8

What are the factors of (r+t)(e)

Mathematics
1 answer:
mina [271]4 years ago
7 0

Depending on the values of  'r',  't', and  'e', the numerical value of that expression
might have many factors. 

For example, if it happens that r=5, t=1, and e=4 for an instant, then, just
for a moment,  (r + t)(e) = (5+1)(4) = 24, and the factors of (r+t)(e) are
1,  2,  3,  4,  6,  8,  12, and  24 .   But that's only a temporary situation.

The only factors of (r+t)(e) that don't depend on the values of  'r',  't',  or  'e' ,
and are always good, are  (<em>r + t</em>)  and  (<em>e</em>) .

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Answer:

Use Pythagorean theorm.

a^2 + b^2 = c^2 (c is hypotenuse).

Let c = 5+b (because in the question it says the hypotenuse is one leg plus 5 more meters) ; we will solve for b and say it's the leg we don't know.

We will say A is the "other leg" we know, which is 6.

6^2 + b^2 = (5+b)^2

We get b = 1.1

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4 years ago
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Put n=4 here so you found

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=31 ans




                             hope it helps

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Answer:

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Step-by-step explanation:

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