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Anuta_ua [19.1K]
3 years ago
12

The sum of 5 consecutive integers is 120. what is the third number in the sequence

Mathematics
2 answers:
rosijanka [135]3 years ago
8 0
The sum of 5 consecutive integers is 120
third number = ?
third number will be the middle number of 5 consecutive integers
so if we divide 120 with 5 we get 24.
so 24 is the third number.
consecutive numbers are: 22, 23,24,25 and 26
22 + 23  +24 +25 +26 = 120
so, 24 is the third number
Lady_Fox [76]3 years ago
3 0

Answer:

24 is the third number

Step-by-step explanation:

I got it right i just did it

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It’s prime because none of the other answers work.
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Solve for x. 3x−1=9x+2 Enter your answer in the box. x =
julia-pushkina [17]

Answer:

x= -1

Step-by-step explanation:

3x-1=2x2 (calculate the product)

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- x = 1 (change the signs)

Solution is x = -1

3 0
3 years ago
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The sum of the first n consecutive even numbers can be found using S=n2+n, where n≥2. What is the value of n when the sum is 42?
lawyer [7]

Answer:

  • C. 6

Step-by-step explanation:

<u>Given</u>

  • S = n² + n
  • S = 42, n = ?

<u>Substitute and solve for n:</u>

  • 42 = n² + n
  • n² + 2*1/2n + 1/4 = 42.25
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  • n + 0.5 = √42.25
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One number is larger than another by 9. If the greater number is increased by 10, and the lesser number is tripled, the sum of t
kkurt [141]

Answer:

The larger number is -6, the smaller number is -15

Step-by-step explanation:

We have two numbers, a and b.

We know that one number is larger than another by 9.

Then we can write:

a = b + 9

then a is larger than b by 9 units.

If the greater number is increased by 10 (a + 10) and the lesser number is tripled (3*b), the sum of the two would be -41:

(a + 10) + 3*b = -41

So we got two equations:

a = b + 9

(a + 10) + 3*b = -41

This is a system of equations.

One way to solve this is first isolate one variable in one of the two equations:

But we can see that the variable "a" is already isolated in the first equation, so we have:

a = b + 9

now we can replace that in the other equation:

(a + 10) + 3*b = -41

(b + 9) + 10 + 3*b = -41

now we can solve this for b.

9 + b + 10 + 3b = -41

(9 + 10) + (3b + b) = -41

19 + 4b = -41

4b = -41 -19 = -60

b = -60/4 = -15

b = -15

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a = b + 9

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a = -6

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