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scoundrel [369]
3 years ago
14

Which equation should be used to calculate S9 for the arithmetic sequence an=3n-1

Mathematics
2 answers:
bagirrra123 [75]3 years ago
8 0

Answer:

Option A is correct.

The equation = S_9 =\frac{9}{2} (2+26).

Explanation:

Sum of the terms of an arithmetic series is given by

S_n = \frac{n(a_1+a_n)}{2},                  ......[1]

where n is the number of terms, a_1 is the first term and  a_nis the last term.

Given the formula for nth term in the arithmetic sequence is, a_n = 3n-1

for n =1

a_1 = 3 \cdot 1 -1 = 3-1 =2

for n =9

a_9= 3 \cdot 9 -1 = 27-1 =26

Then, put these values in equation [1] for n =9;

S_9 = \frac{9 \cdot (a_1+a_9)}{2} = \frac{9(2+26)}{2} or

S_9 =\frac{9}{2} (2+26)

Therefore, the equation is; S_9 =\frac{9}{2} (2+26)




EastWind [94]3 years ago
7 0

Answer:

1. D

2. A

3. C

4. D

5. A

Step-by-step explanation:

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myrzilka [38]
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=========================================================

Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

Marginal cost = derivative of cost function

Marginal cost = C ' (x)

Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.

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C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

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Therefore, we go from this

C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

to this

C(x) = 15x^{7/3} - 8x^{7/4} + x + 9000\\\\

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Answer:

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Step-by-step explanation:

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