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tigry1 [53]
3 years ago
10

Examine figure 26-1 which area is the convection zoneA. AB. BC. CD. D

Physics
2 answers:
zloy xaker [14]3 years ago
5 0

Answer:

B.   B

Explanation:

As we know that convective zone is that part of the sun where heat is primarily transferred by convection mode. In this part of sun major proportion is gas so that heat is transferred by gas molecules.

So here we will have

outer most part of the sun is E = CORONA

then it is the surface of sun which is A = PHOTO SPHERE

Then the inner part to the surface of sun is B = CONVECTIVE ZONE

then the next inner part is vacuum where heat is transfer by C = RADIATE ZONE

Then the innermost part of the sun is its D = CORE

so correct answer will be B

kykrilka [37]3 years ago
4 0
I think the answer is B
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Answer:

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Explanation:

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3 years ago
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Answer: 0.55 m/s

Explanation:

This situation is related to projectile motion (also called parabolic motion), where the main equations are as follows:

x=V_{o} cos\theta t (1)

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Where:

x=0.25 m is the horizontal displacement of the pencil

V_{o} is the pencil's initial velocity

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y_{o}=1 m  is the initial height of the pencil

y=0  is the final height of the pencil (when it finally hits the ground)

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Begining with (1):

x=V_{o} cos(0\°) t (3)

x=V_{o}t (4)

Finding t from (2):

0=1 m+ \frac{-9.8m/s^{2}}{2}t^{2} (5)

t=\sqrt{\frac{-2y_{o}}{g}} (6)

Substituting (6) in (4):

x=V_{o}\sqrt{\frac{-2y_{o}}{g}} (7)

Isolating V_{o}:

V_{o}=\frac{x}{\sqrt{\frac{-2y_{o}}{g}}} (8)

V_{o}=\frac{0.25 m}{\sqrt{\frac{-2(1 m)}{-9.8m/s^{2}}}} (9)

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V_{o}=0.55 m/s

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3 years ago
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