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tigry1 [53]
4 years ago
10

Examine figure 26-1 which area is the convection zoneA. AB. BC. CD. D

Physics
2 answers:
zloy xaker [14]4 years ago
5 0

Answer:

B.   B

Explanation:

As we know that convective zone is that part of the sun where heat is primarily transferred by convection mode. In this part of sun major proportion is gas so that heat is transferred by gas molecules.

So here we will have

outer most part of the sun is E = CORONA

then it is the surface of sun which is A = PHOTO SPHERE

Then the inner part to the surface of sun is B = CONVECTIVE ZONE

then the next inner part is vacuum where heat is transfer by C = RADIATE ZONE

Then the innermost part of the sun is its D = CORE

so correct answer will be B

kykrilka [37]4 years ago
4 0
I think the answer is B
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zysi [14]

Answer:

Magneta is a mix of blue and red and is a secondary colour.

Explanation:

As we can see green is the complementary colour of Magneta.Complementary colours are the pairs of colours which when combined cancel each other out. This means that when combined they produce a grayscale colour like white or black .

4 0
3 years ago
A car travels due east with a speed of 52.0 km/h. Raindrops are falling at a constant speed vertically with respect to the Earth
serg [7]

Answer:

a) v = 6.43 m/s

b) v = 15.8 m/s

Explanation:

Speed of car = 56 km/h

56 km/h = 14.4 m/s

Angle rain makes on the glass to the vertical = 66°

Thus knowing that the opposite side of the angle is the distance moved by the car, and the adjacent side is the distance traveled by the rain in the same time

both of which are directly proportional to their velocities

Then

tan(66°) = 14.44m/s ÷ x

or x = 14.44/tan(66°)

Which is the vertical raindrop velocity of the relative to earth

v = 6.43 m/s vertically towards earth

For v relative to the car is we have vector sum of both velocities

v = √(14.44^2 + 6.43^2) = 15.8 m/s which is the velocity relative to car

= 15.8 m/s

6 0
3 years ago
A 10 kg bear is running to the right at 10 m/s. He crashes into another 10 kg bear running to the left at -5 m/s. They collide a
faust18 [17]

Answer:

<em>Total momentum is conserved</em>

Explanation:

<u>Conservation of Momentum </u>

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p=m_1v_1+m_2v_2=(10)(10)+(10)(-50)=50\ kg.m/s

When both bears stick together, the total mass is 20 kg, and the new momentum is

p'=(20)(2.5)=50 \ kg.m/s

We have assumed both bears move to the right after the collision. In this situation, the total momentum is conserved

7 0
3 years ago
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Xelga [282]

Answer:

y e s :))))))))))))))))))))))))))))))))

Explanation:

y - dirdf leter of di alfabet

3 0
3 years ago
An object possessing an excess of 6.0x10^6 electrons has a net charge of
guajiro [1.7K]
A single electron has a charge of
e=-1.6 \cdot 10^{19}C
Therefore, if we have an excess of N=6.0\cdot10^6 electrons, the total net charge will be the product between the charge of a single electron and the total number of electrons in excess:
Q=Ne=(6.0\cdot10^6)(-1.6 \cdot 10^{-19}C)=9.6 \cdot 10^{-13}C
7 0
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