Answer: 0.03 N/C
Explanation:
We use the current density formula to solve this question.
I/A = σ * E
Where,
I = current flowing in the circuit = 0.3 A
A = cross sectional area of the wire = 1 mm²
σ = resistivity of the wire = 1*10^7 Ω^-1·m^-1
E = strength of the electric field required
I/A = σ *E
E = I/(A * σ)
First we convert area from mm to m, so that, 1*10^-3 mm = 1*10^-6 m
E = 0.3 A / (1*10^-6 m * 1*10^7 Ω^-1·m^-1)
E = 0.3 A / 10 Ω^-1
E = 0.03 N/C
The spider will cross the driveway <u>25.71 in seconds</u>.
Why?
It's a conversion problem, so, in order to solve it, we need to convert the units of the given information.
Let's convert the given speed (in cm/s) to m/s.
We know that:
So, converting we have:
Then, calculating the time, we have:
We have that the spider will cross the driveway in 25.71 seconds.
Have a nice day!
Speed= f x λ ( f= frequency. λ = wavelength)
Speed = 2Hz x 6m
= 12m/s
The key thing we look for is <u>WATER.</u> We need to analyze whether a world is a possible home to life if it has the past, present, and future existence of liquid water.
Even if the planet has evidence of atmospheric oxygen, it is still insufficient for humans to live in it if it lacks H2O.
Some may argue that the presence of organic molecules such as amino acids should also be taken into account. Even if they have a valid point, it is not the most significant factor that we consider when deciding if the world is a possible home for life.
Aside from water, the world's surface color changes that indicate vegetative growth can be critical in ensuring that the world is habitable. However, vegetative growth is insufficient to be significant if the planet lacks a consistent source of water.
The first confirmed Earth-size planet where liquid water might accumulate on the surface is Kepler-186f. The discovery of another world provides evidence that there are planets in other stars' habitable zones.
<em>Image Comparison of Earth and Kepler-186f: Both have liquid water.</em><em>
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</em>Learn more about the factors that make the planet habitable: brainly.com/question/18153594
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Answer:
1)m=89.01 g
2)V(max) = 97.3 cm/s
Explanation:
Given that
K= 15 N/m
The maximum amplitude ,A=7.5 cm = 0.075 m
Given that 31 oscillations in 15 seconds ,this means that frequency f
f=\dfrac{31}{15}
f=2.066 Hz
lets take mass of the ball = m kg
m=0.08901 kg
m=89.01 g
The maximum speed
V(max)= ω x A
ω = 2π f= 2 x π x 2.066 = 12.98 rad/s
V(max) = 12.98 x 0.075 =0.973 m/s
V(max) = 97.3 cm/s