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2 years ago

How long has a victim been dead if his body temperature was 89.2°F?

Physics

2 answers:

Zanzabum2 years ago

8 0

Answer: too long lolz

Explanation:

Too long

denis-greek [22]2 years ago

7 0

The body loses 1.5 degrees of temperature per hour. Depending on the environment of course.
The body’s regular temperature is 98.6 so 98.6-89.2= 9.4
9.4 divided by 1.5 is about 6.2 hours.
But this is just what I know this is not a guaranteed solution.

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Which machine can create images of atoms?

Svetradugi [14.3K]

Answer: Scanning Tunneling Microscope

Explanation:

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2 years ago

Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerate

maria [59]

Complete Question

Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?

Answer:

Go-cart A is faster

Explanation:

From the question we are told that

The length of the track is $l = 1.0 \ km = 1000 \ m$

The speed of A is $v__{A}} = 20 \ m/s$

The uniform acceleration of B is $a__{B}} = 0.333 \ m/s^2$

Generally the time taken by go-cart A is mathematically represented as

$t__{A}} = \frac{l}{v__{A}}}$

=> $t__{A}} = \frac{1000}{20}$

=> $t__{A}} = 50 \ s$

Generally from kinematic equation we can evaluate the time taken by go-cart B as

$l = ut__{B}} + \frac{1}{2} a__{B}} * t__{B}}^2$

given that go-cart B starts from rest u = 0 m/s

$1000 = 0 *t__{B}} + \frac{1}{2} * 0.333 * t__{B}}^2$

=> $1000 = 0 *t__{B}} + \frac{1}{2} 0.333 * t__{B}}^2$

=> $t__{B}} = 77.5 \ seconds$

Comparing $t__{A}} \ and \ t__{B}}$ we see that $t__{A}}$ is smaller so go-cart A is faster

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2 years ago

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vivado [14]

Answer:

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Explanation:

ratio of number of orbits, so it completes 7 orbits in the time Janus does 6.

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Answer:

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Nezavi [6.7K]

Answer:

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Explanation:

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