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Archy [21]
3 years ago
9

How long has a victim been dead if his body temperature was 89.2°F?

Physics
2 answers:
Zanzabum3 years ago
8 0

Answer: too long lolz

Explanation:

Too long

denis-greek [22]3 years ago
7 0
The body loses 1.5 degrees of temperature per hour. Depending on the environment of course.
The body’s regular temperature is 98.6 so 98.6-89.2= 9.4
9.4 divided by 1.5 is about 6.2 hours.
But this is just what I know this is not a guaranteed solution.
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Two metra trains approach each other on separate but parallel tracks. one has a speed of 90 km/hr, the other 80 km/hr. initially
Gennadij [26K]

The trains take <u>57.4 s</u> to pass each other.

Two trains A and B move towards each other. Let A move along the positive x axis and B along the negative x axis.

therefore,

v_A=90 km/h\\ v_B=-80 km/h

The relative velocity of the train A with respect to B is given by,

v_A_B=v_A-v_B\\ =(90km/h)-(-80km/h)\\ =170km/h

If the train B is assumed to be at rest, the train A would appear to move towards it with a speed of 170 km/h.

The trains are a distance d = 2.71 km apart.

Since speed is the distance traveled per unit time, the time taken by the trains to cross each other is given by,

t= \frac{d}{v_A_B}

Substitute 2.71 km for d and 170 km/h for v_A_B

t= \frac{d}{v_A_B}\\ =\frac{2.71 km}{170 km/h} \\ =0.01594 h

Express the time in seconds.

t=(0.01594h)(3600s/h)=57.39s

Thus, the trains cross each other in <u>57.4 s</u>.

6 0
3 years ago
Kristen is running a half marathon. By her tenth minute of running, her breathing rate has increased from her resting rate.
pashok25 [27]
They need more oxygen to function, so gas exchange needs to increase
7 0
3 years ago
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A capacitor with a very large capacitance is in series with a capacitor that has a very small capacitance. what can we say about
Misha Larkins [42]
<span>A capacitor with a very large capacitance is in series with a capacitor
that has a very small capacitance.

The capacitance of the series combination is slightly smaller than the
capacitance of the small capacitor. (choice-C)

The capacitance of a series combination is

             1 / (1/A + 1/B + 1/C + 1/D + .....) .

If you wisk, fold, knead, and mash that expression for a while,
you find that for only two capacitors in series, (or 2 resistors or
two inductors in parallel), the combination is   

             (product of the 2 individuals) / (sum of the individuals)  .

In this problem, we have a humongous one and a tiny one.
Let's call them  1000  and  1 .
Then the series combination is

           (1000 x 1) / (1000 + 1)

        =       (1000) / (1001)

        =         0.999 000 999 . . . 

which is smaller than the smaller individual.

It'll always be that way.   </span>
5 0
3 years ago
How many Newtons of force does it take to move a 53 kilogram object?
Sidana [21]
519.75N

explanation: good luck on whatever assignment
3 0
3 years ago
Which of the following is not a galilean moon?
REY [17]
The answer is B) titan
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