Ask question

Ask question

All categories

3 years ago

9

How long has a victim been dead if his body temperature was 89.2°F?

2 answers:

Zanzabum3 years ago

8 0

Answer: too long lolz

Explanation:

Too long

denis-greek [22]3 years ago

7 0

The body loses 1.5 degrees of temperature per hour. Depending on the environment of course.
The body’s regular temperature is 98.6 so 98.6-89.2= 9.4
9.4 divided by 1.5 is about 6.2 hours.
But this is just what I know this is not a guaranteed solution.

You might be interested in

10. A 90 kg box is sliding across a surface at a constant velocity while experiencing a rightward applied

ANEK [815]

If the box is moving at constant velocity, net force must be zero, so:

F + fr = 0

fr = -F

<u>fr = -40 N</u>

4 0

3 years ago

Read 2 more answers

How do lenses and mirrors compare in their interactions with light?

slamgirl [31]

D. lenses focus light , mirrors do not

7 0

2 years ago

Read 2 more answers

The amplitude of a wave<br> determines the volume of a<br> sound.<br> True<br> O False

Vikki [24]

True the amplitude of a wave determines the volume of a sound

6 0

2 years ago

A 2.5 kg block is launched along the ground by a spring with a spring constant of 56 N/m. The spring is initially compressed 0.7

Norma-Jean [14]

vf ^2 = kx^2/m = 56(0.75)^2 / 2.5 = 12.6

Therefore, v= 3.5 m/s.

7 0

3 years ago

Read 2 more answers

Which temperature is the hottest? 98 F or 39 C or 303K?<br> F= 1.8C + 32<br> C= (F-32)/1.8

sergejj [24]

Answer:

The hottest temperature is $T_2 = 39^o C$

Explanation:

From the question we are given

$T_1 = 98 F$

$T_2 = 39^oC$

$T_3 = 303 \ K$

Generally converting $T_3$ to Fahrenheit

$T_3' = (T_3 -273 ) * \frac{9}{5} + 32$

=> $T_3' = (303 -273 ) * \frac{9}{5} + 32$

=> $T_3' = 86 F$

Converting $T_2$ to Fahrenheit

$T_2' = T_2 * \frac{9}{5} + 32$

=> $T_2' = 39 * \frac{9}{5} + 32$

=> $T_2' =102.2 F$

Now comparing the temperature in Fahrenheit we see that $T_2$ is the hottest

3 0

3 years ago