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3 years ago

Giving choices helps children by

Physics

2 answers:

mr Goodwill [35]3 years ago

8 0

Answer:

Explanation:

Giving children choices can allow them to build the necessary skills of decision making in the real world when they grow up.

For example, a child is posed with the option of eating a sweet now, or waiting until the next day and receive two sweets. This will enable the child to develop the skill of making decisions that will benefit them one day, because they are now thinking about the future, instead of living in the moment.

So with the example above, they can use this skill in the real world of investing, but instead of sweets, the options could be related to money (eg. I could buy a second-hand car now, or I could save and buy a brand new car next year).

MissTica3 years ago

5 0

A.

Experiencing frustration is normally caused by a lack of options.

Don't really know why the other two are even here.

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1. A rocket is forced forward by the ______ force of its engines, expelling gases out the rear of the rocket.

AURORKA [14]

There are two forces acting on a rocket at the moment of lift off: Thrust pushes the rocket upwards by pushing gases downwards in the opposite direction.Weight is the force due to gravity pulling the rocket downwards towards the centre of the earth.So I'm thinking the answer is THRUST.

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2 years ago

Suppose you illuminate two thin slits by monochromatic coherent light in air and find that they produce their first interference

strojnjashka [21]

Answer:

1.7323

Explanation:

To develop this problem, it is necessary to apply the concepts related to refractive indices and Snell's law.

From the data given we have to:

$n_{air}=1$

$\theta_{liquid} = 19.38\°$

$\theta_{air}35.09\°$

Where n means the index of refraction.

We need to calculate the index of refraction of the liquid, then applying Snell's law we have:

$n_1sin\theta_1 = n_2sin\theta_2$

$n_{air}sin\theta_{air} = n_{liquid}sin\theta_{liquid}$

$n_{liquid} = \frac{n_{air}sin\theta_{air}}{sin\theta_{liquid}}$

Replacing the values we have:

$n_{liquid}=\frac{(1)sin(35.09)}{sin(19.38)}$

$n_liquid = 1.7323$

Therefore the refractive index for the liquid is 1.7323

6 0

3 years ago

The coefficient of the restitution of an object is defined as the ratio of its outgoing to incoming speed when the object collid

IgorLugansk [536]

Answer:

48.16 %

Explanation:

coefficient of restitution = 0.72

let the incoming speed be = u

let the outgoing speed be = v

kinetic energy = 0.5 x mass x $x velocity^{2}$

incoming kinetic energy = 0.5 x m x $x u^{2}$

coefficient of restitution = $\frac{v}{u}$

0.72 = $\frac{v}{u}$

v = 0.72u

therefore the outgoing kinetic energy = 0.5 x m x $(0.72u)^{2}$

outgoing kinetic energy = 0.5 x m x $0.5184 x u^{2}$

outgoing kinetic energy = 0.5184 (0.5 x m x $x u^{2}$ )

recall that 0.5 x m x $x u^{2}$ is our incoming kinetic energy, therefore

outgoing kinetic energy = 0.5184 x (incoming kinetic energy)

from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.

The energy lost would be 100 - 51.84 = 48.16 %

5 0

3 years ago

A 46.0-kg box is being pushed a distance of 8.80 m across the floor by a force P whose magnitude is 171 N. The force P is parall

dolphi86 [110]

Answer:

a) 1504.8 J

b) 991.76 J

c) 0J

d) 0J

Explanation:

(a) The work done by the force P on the box is given by the following formula:

$W_P=Px$

P: applied force = 171N

x: distance in which the for P is applied = 8.80m

you replace the values of P and x and obtain:

$W_P=(171N)(8.80m)=1504.8J$

(b) The work don by the friction force is:

$W_f=F_fx=\mu N x=\mu Mg x$

μ = coefficient of kinetic friction = 0.250

M: mass of the box = 46.0kg

g: gravitational constant = 9.8 m/s^2

$W_f=(0.250)(46.0kg)(9.8m/s^2)(8.80m)=991.76J$

$N=Mg=(46.0kg)(9,8m/s^2)=450.8N$

but this force does not do work on the box because the direction is perpendicular to the direction of the force P.

$W_N=0J$

(d) the same as before:

$W_g=0J$

8 0

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LenKa [72]

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3 0

3 years ago

Read 2 more answers