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WARRIOR [948]
3 years ago
15

Summers are caused by

Physics
2 answers:
alexandr1967 [171]3 years ago
4 0

it is A hope it is useful.

Zigmanuir [339]3 years ago
4 0

Answer:

Summers are caused combination of longer days and more direct rays from the sun.

Explanation:

Summers are caused combination of longer days and more direct rays from the sun.

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1. While driving to Palm Desert you notice that some of the windmills near the freeway are spinning 20 times per minute. The len
igomit [66]

Answer:

a) \alpha = -0.233 rad/s^{2}

b) the rotational acceleration will remain the same,  \alpha = -0.233 rad/s^{2}

c) When r = 36 m, a_{c} = 157.25 m/s^{2}

   When r = 18 m, a_{c} = 78.63 m/s^{2}

d) When r = 36 m, a_{c} = 39.31 m/s^{2}

   When r = 36 m, a_{c} = 19.66 m/s^{2}

Explanation:

The windmills are spinning 20 times per minute, the number of spins in 1 second = 20/60  = 1/3 spins/sec

frequency, f = 1/3 spins/sec

there are 1/3 spins in 1 second,

there will be 50 spins in 50/ (1/3) seconds = 150 seconds

i.e time taken to make 50 spins = 150 seconds

Time interval between 20 and 50 spins, Δt = 150 - 60 = 90

Δt = 90

Angular frequency at 20 spins:

w₁ = 2 π f

w₁ = 2 π * 1/3 = 2π/3 = 2.09 rad/s

Since the blade stops at 50 spins, angular frequency at 50 spins, w₂ = 0

The rotational acceleration,

\alpha = \frac{\triangle w}{\triangle t} \\\alpha = \frac{w_{2} - w_{1} }{\triangle t} \\\alpha = \frac{0 - 2.09 }{90} \\\alpha = -0.233 rad/s^{2}

b) The magnitude of the rotational acceleration does not depend on the radius, r. It depends on the angular frequency, therefore the magnitude of the rotational acceleration doe not change.

c) The centripetal acceleration is given by the formula, a_{c} = w^{2} r

While the windmill spins at 20 times per minute, the angular speed gotten, w = 2.09 rad/s

When r = 36 m

a_{c} = 2.09^{2} * 36\\a_{c} = 157.25 m/s^{2}

At the halfway point, r = 18 m

a_{c} = 2.09^{2} * 18\\a_{c} = 78.63 m/s^{2}

d) If the angular velocity of the blades were cut in halves:

w = 2.09/2

w = 1.045 rad/s

When r = 36 m

a_{c} = 1.045^{2} * 36\\a_{c} = 39.31 m/s^{2}

When r = 18 m

a_{c} = 1.045^{2} * 18\\a_{c} = 19.66 m/s^{2}

8 0
3 years ago
A child on a playground swings through a total of 32 degrees. If the displacement is equal on each side of the equilibrium posit
Black_prince [1.1K]

Answer: A = y/cos32

That is the amplitude A in terms of the displacement y.

Explanation: Since the displacement in the question In the question is the same in both direction, it is a Simple Harmonic Motion problem. In s.h.m the amplitude of displacement A is related to the displacement itself y by this simple equation

y = A* cos(theta)

So, A = y/cos(theta)

A = y/cos32.

If the magnitude of the displacement y is given, you just substitute in.

4 0
3 years ago
50 Points Please Help Me for Physics
GalinKa [24]

Explanation:

met I'd => 86189778400

pas code => g0cg6V

come on g met => spd-mwbz-een

3 0
3 years ago
Read 2 more answers
The change in momentum (and impulse) are still 3000 N*s. Safety devices (like airbags, seatbelts and crumple zones) cause crashe
aleksklad [387]

Answer:

F = 2000 N

Explanation:

According to Newton's Second Law of Motion, the rate of change of momentum is equal to the force applied. Therefore, the formula written below will be used to solve this problem:

F = \frac{\Delta P}{t}\\\\

where,

F = Force everted = ?

ΔP = Cange in Momentum = 3000 N.s

t = time taken = 1.5 s

Therefore,

F = \frac{3000\ N.s}{1.5\ s}

<u>F = 2000 N</u>

5 0
3 years ago
At a certain instant the current flowing through a 5.0-H inductor is 3.0 A. If the energy in the inductor at this instant is inc
lys-0071 [83]

Answer:

The current is changing at the rate of 0.20 A/s

Explanation:

Given;

inductance of the inductor, L = 5.0-H

current in the inductor, I = 3.0 A

Energy stored in the inductor at the given instant, E = 3.0 J/s

The energy stored in inductor is given as;

E = ¹/₂LI²

E = ¹/₂(5)(3)²

E = 22.5 J/s

This energy is increased by 3.0 J/s

E = 22.5 J/s + 3.0 J/s = 25.5 J/s

Determine the new current at this given energy;

25.5 = ¹/₂LI²

25.5 = ¹/₂(5)(I²)

25.5 = 2.5I²

I² = 25.5 / 2.5

I² = 10.2

I = √10.2

I = 3.194 A/s

The rate at which the current is changing is the difference between the final current and the initial current in the inductor.

= 3.194 A/s - 3.0 A/s

= 0.194 A/s

≅0.20 A/s

Therefore, the current is changing at the rate of 0.20 A/s.

5 0
3 years ago
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