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lara [203]
2 years ago
10

A 1600 kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2000 kg SUV traveling from ea

st to west. The two cars become enmeshed due to the impact and slide as one thereafter. On-the-scene measurements show that the coefficient of kinetic friction between the tires of these cars and the pavement is 0.75, and the cars slide to a halt at a point 5.42 m west and 6.37 m south of the impact point.How fast was sedan traveling just before the collision? How fast was SUV traveling just before the collision?

Physics
1 answer:
skad [1K]2 years ago
4 0

Answer:

v = 11.1m/s

Vx = 7.19m/s

Vy = 8.45m/s

V(sedan) = 30.4m/s

V(suv) = 25.9m/s

Explanation:

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Select the correct answer. Which statement is true about a polarized object? A. It gains electrons and becomes negatively charge
coldgirl [10]

Answer:

C. The number of positive and negative charges can be the same.

Explanation:

3 0
3 years ago
If two runners take the same amount of time to run a mile, they have the same __________.
Elan Coil [88]

None of the choices is correct.

If two runners take the same amount of time to run a mile,
they have the same average speed.  But their velocities
are not the same unless both runners begin and end their
run at the same points.

Speed is   (distance covered) divided by (time to cover the distance).

Velocity is not.  It's something different. 
'Velocity' is not just a bigger word for 'speed'.

3 0
3 years ago
Read 2 more answers
For a wire has a circular cross section with a radius of 1.23mm.
Mila [183]

Answer:

5.731\times 10^{-5}\ m/s

Decrease

Explanation:

I = Current = 3.7 A

e = Charge of electron = 1.6\times 10^{-19}\ C

n = Conduction electron density in copper = 8.49\times 10^{28}\ electrons/m^3

v_d = Drift velocity of electrons

r = Radius = 1.23 mm

Current is given by

I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s

The drift speed of the electrons is 5.731\times 10^{-5}\ m/s

v_d=\dfrac{I}{neA}

From the equation we can see the following

v_d\propto \dfrac{1}{n}

So, if the number of conduction electrons per atom is higher than that of copper the drift velocity will decrease.

5 0
3 years ago
When 1,250^3/4 is written in simplest radical form, which value remains under the radical?
GaryK [48]

Answer:

125\sqrt[4]{8}

Explanation:

A number of the form

a^{\frac{m}{n}}

can be re-written in the radical form as follows:

\sqrt[n]{a^m}

In this problem, we have:

a = 1,250

m = 3

n = 4

So, if we apply the formula, we get

1,250^{\frac{3}{4}}=\sqrt[4]{(1,250)^3}

Then, we can rewrite 1250 as

1250 = 2\cdot 5^4

So we can rewrite the expression as

=\sqrt[4]{(2\cdot 5^4)^3}=5^3 \sqrt[4]{2^3}=125\sqrt[4]{8}

7 0
3 years ago
Read 2 more answers
Which one of the following scenarios accurately describes a condition in which resonance can occur? A. A column of air has a hei
Butoxors [25]
The correct option is B.
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2. A force that is functioning at the same frequency as the natural frequency.
3. Prevention of energy loss.
4 0
2 years ago
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