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Andrej [43]
3 years ago
10

What forces contribute to density

Physics
1 answer:
mixer [17]3 years ago
5 0
No force contributes to density, the density is a physical quantity that is defined as being \rho = m/V 
 the raport between the mass of the object and its volume. However if you want to measure the density of an object you might want to determine its gravity force (weight) G=mg from which knowing the gravitational acceleratin you can find its mass m=G/g
 
where G is given in Newtons and g=9.81 is given in  (m/s^2)


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A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that a
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To solve this problem we will apply the concepts related to magnetic flux and induced voltage. This last expression understood as the variation of the magnetic flux over time and, in turn, the magnetic flux expressed as the variation of the magnetic field in a certain area.

Magnetic flux through the circular coil is given as

\Phi_C = B(\pi r^2)

The induced voltage is the change of the magnetic flux across the time, then

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At the same time the magnetic flux through the square coil would be given as,

\Phi_S = B(r^2)

And the induced voltage EMF will be

\epsilon_{emf,s} = \frac{B(r^2)}{t}

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3 years ago
Which best distinguishes between the inner and outer planets?
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4 years ago
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ustapha Jones is speeding on the interstate in his Ferrari at 231km/hr when he passes a police car at rest . If the cop accelera
Lena [83]

Answer:

461 km/h

Explanation:

In order to solve this problem we must first sketch a drawing of what the situation looks like so we can better visualize it. (See attached picture).

We have two situations there, the first one is Mustapha's car that is traveling at a constant speed of 231km/hr.

The second situation is the police that is accelerating from rest until he reaches Mustapha. (We are going to suppose the acceleration is constant and that he will not stop accelerating until he reaches Mustapha). He has an acceleration of 15m/s^{2}.

We want to find what the final velocity of the police is at the time he reaches Mustapha. From this we can imply that the displacement x will be the same for both particles.

So let's model the first situation.

The displacement of Mustapha can be found by using the following equation:

V_{M}=\frac{x}{t}

when solving the equation for the displacement x we get that it will be:

x=V_{M}t

Now let's model the displacement of the cop. Since the cop has a constant acceleration, we can model his displacement with the following formula.

x=V_{0}t+\frac{1}{2}at^{2}

Since the initial velocity of the cop is zero, we can get rid of that part of the equation leaving us with:

x=\frac{1}{2}at^{2}

We can now set both equations equal to each other so we get:

\frac{1}{2}at^{2}=V_{M}t

When solving this for t, we get that:

t=\frac{2V_{M}}{a}  (let's call this equation 1)

Now, we know the cop has constant acceleration, so we can model it with the following formula too:

a=\frac{V_{f}-V_{0}}{t}

since the initial velocity of the cop is zero, we can get rid of that here too, so we get the following formula:

a=\frac{V_{f}}{t}

when solving for the final velocity, we get that:

V_{f}=at  (let's call this equation 2)

when substituting equation 1 into equation 2 we get:

V_{f}=a(\frac{2V_{M}}{a})

we can now cancel a leaving us with:

V_{f}=2V_{M}

This tells us that the final velocity of the cop will not depend on his acceleration. (This is only if the acceleration is constant all the time) So we get that the final velocity of the cop is:

V_{f}=2(231km/hr)

so

V_{f}=461km/hr

which is our answer.

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