Why is the reactor coolant water kept contained within the primary loop instead of allowing it to mix with the feed water and le
2 answers:
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Answer:
(a). The initial rate is 2.60 A/s.
(b). The rate of current increases is 0.8658 A/s.
(c). The current is 0.435 A.
(d). The final steady-state current is 0.75 A.
Explanation:
Given that,
Inductance = 2.30 H
Resistance = 8.00 Ω
Voltage = 6.00 V
(a). We need to calculate the initial rate of increase of current in the circuit.
Using formula of initial rate
Put the value into the formula
The initial rate is 2.60 A/s.
(b). We need to calculate the rate of increase of current at the instant when the current is 0.500
Using formula of rate of increase of current
....(I)
Where,
Using formula of current
The rate of current increases is
Put the value in the equation (I)
The rate of current increases is 0.8658 A/s.
(c). We need to calculate the current
Using formula of current
Put the value into the formula
The current is 0.435 A.
(d). We need to calculate the final steady-state current
Using formula of steady state
The final steady-state current is 0.75 A.
Hence, This is the required solution.