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tamaranim1 [39]
3 years ago
9

Plz answer this very soon

Physics
2 answers:
kherson [118]3 years ago
7 0

Answer:

a

hope u get a hundred

Explanation:

tester [92]3 years ago
6 0

Answer:

Im gonna say it is answer A:) Hope this helps!

Explanation:

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An athlete runs at a constant velocity of 5.2 m/s. What is the velocity of the athlete relative to the ground?
dimulka [17.4K]

The relative velocity of the athlete relative to the ground is 5.2 m/s

The given parameters;

constant velocity of the athlete, V = 5.2 m/s

let the velocity of the ground = Vg = 0

The relative velocity concept helps us to determine the velocity of a moving object relative to a stationary observer.

The athlete is the moving object in this question while the ground is stationary.

The relative velocity of the athlete relative to the ground is calculated as follows;

V/V_g = V - V_g  = 5.2 - 0 = 5.2  \ m/s

Thus, the relative velocity of the athlete relative to the ground is 5.2 m/s

Learn more here: brainly.com/question/24430414

5 0
3 years ago
Two differences between science activities carried out in a science laboratory and those carried out side of science laboratory.
viva [34]

In a science lab, there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isn't.

In a science lab, the availability of apparatuses and sources of heat is higher than outside a science lab.

<h3>What is science laboratory?</h3>

The science lab is a place where the experiments related to the science background are performed with the use of apparatus.

The science lab has plenty of equipment to perform the experiment whether related to physics or chemistry or biology.

Thus, source of heat and availability of raw material and equipment are the differences between the science activities carried out in a science laboratory and those carried out side of science laboratory.

Learn more about science laboratory.

brainly.com/question/7412101

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8 0
2 years ago
Read 2 more answers
A bullet with a mass ????b=13.5 g is fired into a block of wood at velocity ????b=249. The block is attached to a spring that ha
larisa86 [58]

Answer:

M = 0.436 kg

Explanation:

As per energy conservation we can say that energy stored in the spring at the position of maximum compression must be equal to the kinetic energy of bullet and block system

so here we have

\frac{1}{2}(m + M)v^2 = \frac{1}{2} kx^2

here we know that

k = 205 N/m

x = 35 cm

\frac{1}{2}(m + M)v^2 = \frac{1}{2}(205)(0.35)^2

now by momentum conservation we know that

mv_o = (m + M)v

v = \frac{m}{m + M} v_o

now plug in all values in it

v = \frac{0.0135}{0.0135 + M}(249)

now from above equation

\frac{1}{2}(0.0135 + M)( \frac{0.0135}{0.0135 + M}(249))^2 = 12.56

\frac{5.65}{0.0135 + M} = 12.56

by solving above equation we have

M = 0.436 kg

3 0
3 years ago
There are four springs stretched by the same mass.
kirill115 [55]

Answer:

That would be Spring C

Explanation:

i took the test :P

6 0
4 years ago
Excited hydrogen atoms radiate energy in the _________
sveticcg [70]

Answer:

infrared, visible and ultraviolet regions.

Explanation:

7 0
3 years ago
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