The electric potential energy of the point charge is 4.
the electric potential energy of the point charge at 1.3 m is 5.2.
Answer:
Acceleration, 
Explanation:
Initial velocity of a particle in vector form, u = (-5i - 2j) m/s
Final velocity of particle in vector form, v = (-6i + 7j) m/s
Time taken, t = 8 seconds
We need to find the magnitude of acceleration vector. The changing of velocity w.r.t time is called acceleration of a particle. It is given by :

or

Hence, the value of acceleration vector is solved.
A: is potential
C: is losing kinetic energy and gaining potential energy
B: kinetic energy is at its highest
D: is loosing potential energy and gaining kinetic energy
Answer:
DS = 13865.7[J/K]
Explanation:
We can calculate the energy of the rock, like the potential energy relative to the lake level. Which can be calculated by means of the following expression of the potential energy:
![E_{p}=m*g*h\\\\where:\\m = mass = 2000[kg]\\h = elevation = 200 [m]\\g = gravity = 9.81[m/s^2]](https://tex.z-dn.net/?f=E_%7Bp%7D%3Dm%2Ag%2Ah%5C%5C%5C%5Cwhere%3A%5C%5Cm%20%3D%20mass%20%3D%202000%5Bkg%5D%5C%5Ch%20%3D%20elevation%20%3D%20200%20%5Bm%5D%5C%5Cg%20%3D%20gravity%20%3D%209.81%5Bm%2Fs%5E2%5D)
Therefore:
![E_{p}=2000*9.81*200\\E_{p}=3924000 [J]\\](https://tex.z-dn.net/?f=E_%7Bp%7D%3D2000%2A9.81%2A200%5C%5CE_%7Bp%7D%3D3924000%20%5BJ%5D%5C%5C)
This energy is transformed into thermal energy.
we shall remember that isothermal heat transfer processes are internally reversible, so the entropy change of a system during one of these processes can be determined, by the following expression.
![DS=\frac{Q}{T}\\ where:\\DS = entropy change [J/K]\\Q = Heat transfer [J]\\T = temperature [K]](https://tex.z-dn.net/?f=DS%3D%5Cfrac%7BQ%7D%7BT%7D%5C%5C%20where%3A%5C%5CDS%20%3D%20entropy%20change%20%5BJ%2FK%5D%5C%5CQ%20%3D%20Heat%20transfer%20%5BJ%5D%5C%5CT%20%3D%20temperature%20%5BK%5D)
T = 5 + 278 = 283[K]
DS = 3924000 / 283
DS = 13865.7[J/K]
Answer:
for example the studs are made in football player boot because to increase pressure with descrease in area of surface