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Alenkasestr [34]
3 years ago
10

Traci plans to conduct a coin-flipping experiment to see if the probability of landing on "heads" or "tails" is close to the the

oretical probability of 1 2 . Which experiment is likely to yield a result FARTHEST from the theoretical probability?
Mathematics
1 answer:
Lunna [17]3 years ago
6 0
The experiment with the least number of trials.
 
Experimental probability is more accurate and more close to theoretical probability by having the most trials. More trials = more accuracy. Less trials = less accuracy.
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Please help me! : find the median please
REY [17]

Answer:

#2. 3, #3. 9, #4. 6.2,$ 5. 9,# 6. 16, $7. 4, and #8. 3

Step-by-step explanation:

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Evaluate this problem<br> 8²+18-2(6+2)÷4
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Use the compound interest formulas A = Pert and A = P(1 + ) to solve. Suppose that you have $11,000 to invest. Which investment
gulaghasi [49]

Answer:

Continuously

Step-by-step explanation:

Compounded continuously:

A = Pe^(rt)

A = 11,000 e^(0.0625 × 10)

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Compounded semiannually (twice per year):

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3 0
3 years ago
Is the relation { (5, 2), (-1, 6), (8, -2), (5, 3)} a function? why or why not? list the domain and range
Tasya [4]

Answer:

it is not a function because the input 5 (x) has more than one output (y)

domain (5,-1,8)

range (2,6,-2,3)

Step-by-step explanation:

5 0
3 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
2 years ago
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