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sdas [7]
3 years ago
9

Help will mark most brainliest

Chemistry
2 answers:
kolezko [41]3 years ago
5 0

Answer:

same all i see is a black screen sorry i couldn't help

Explanation:

Fantom [35]3 years ago
4 0
All i are is a black screen
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How many covalent bonds can Carbon, Hydrogen, Nitrogen, Or Oxygen form?
Sergio [31]
Carbon can form four covalent bonds.
Hydrogen can form one covalent bond.
Nitrogen can form three covalent bonds.
Oxygen can form two covalent bonds. 
4 0
3 years ago
A water solution is found to have a molar oh- concentration of 3.2 x 10-5. the solution would be classified as :_______.
Anuta_ua [19.1K]

A water solution is found to have a molar oh- concentration of 3.2 x 10-5. the solution would be classified as neutral.

The concentration of hydroxide ions (OH-) is measured by pOH. It is a way of expressing how alkaline a solution is. At 25 degrees Celsius, aqueous solutions with pOH values of 7 or less are neutral, whereas those with pOH values of 7 or more are acidic. The hydrogen ion potential is known as pH. The potential of hydroxide ions is known as pOH. 2. It is a scale used to estimate the hydrogen ion (H+) concentration in the solution. The hydroxide ion (OH-) concentration of the solution is measured using this scale.

pH + pOH = 14

 pOH = 3.2x 10-5

[OH-] = 10^(-pOH) =10^(- 3.2x 10-5)

= 0.99

7 0
2 years ago
HELP ME PLEASE!!!
krok68 [10]

Answer:

Br (Bromine)

H (Hydrogen)

Explanation:

7 0
3 years ago
Determine the number of molecules in 43.9 g of carbon tetrachloride
ddd [48]

Answer: There are about 0.28 molecules in 43.9 g of carbon tetrachloride. If you are rounding up, it would be 0.3

Explanation:

7 0
2 years ago
The decomposition of carbon disulfide to carbon monosulfide and sulfur is first order with k=2.8 ×10^-7 at 1000°C .What is the h
RoseWind [281]

Answer:

2.5×10⁶ s

Explanation:

From the question given above, the following data were obtained:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

The half-life of a first order reaction is given by:

Half-life (t½) = 0.693 / Rate constant (K)

t½ = 0.693 / K

With the above formula, we can obtain the half-life of the reaction as follow:

Rate constant (K) = 2.8×10¯⁷ s¯¹

Half-life (t½) =?

t½ = 0.693 / K

t½ = 0.693 / 2.8×10¯⁷

t½ = 2.5×10⁶ s

Therefore, the half-life of the reaction is 2.5×10⁶ s

6 0
2 years ago
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