Answer: The compound formed between nitrogen (N) and nitrogen (N) a polar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms.
Explanation:
If electronegativity difference between two atoms is less than 0.4 then bond formed is a pure covalent bond.
If electronegativity difference between two atoms is between 0.4 to 1.8 then bond formed is a polar covalent bond.
If electronegativity difference between two atoms is greater than 1.8 then bond formed is an ionic bond.
The electronegativity value of a nitrogen atom is 3.04. Hence, the electronegativity difference of 
molecule is as follows.
As the electronegativity difference is 0 which is less than 0.4.
Hence, we can conclude that the compound formed between nitrogen (N) and nitrogen (N) a polar covalent bond because there is less than a 0.4 difference in electronegativity between the atoms.
Answer:
C. Its oxidation number increases.
Explanation:
- <em><u>Oxidation is defined as the loss of electrons by an atom while reduction is the gain of electrons by an atom</u></em>.
- Atoms of elements have an oxidation number of Zero in their elemental state.
- When an atom looses electrons it undergoes oxidation and its oxidation number increases.
- For example, <em><u>an atom of sodium (Na) at its elemental state has an oxidation number of 0. When the sodium atom looses an electrons it becomes a cation, Na+, with an oxidation number of +1 , the loss of electron shows an increase in oxidation number from 0 to +1.</u></em>
Answer:
Yes. Since for a substance to be a Bronsted-Lowry acid they have to be able to donate protons, and to be a Lewis acid a substance would have to accept electrons, there are substances which cannot donate protons but can accept electrons.
Explanation:
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